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f(x)=5,000(1.012)^(t)
The function models 
f, the amount of money in Eddie's savings account 
x years after his initial deposit into the account. Which of the following statements is the best interpretation of the ordered pair 
(2,5120.72) ?
Choose 1 answer:
(A) Eddie earned 5,120.72 dollars in interest from his savings account 2 years after his initial deposit.
(B) Eddie has 5,120.72 dollars in his savings account 2 years after his initial deposit.
(C) Eddie has 5,120.72 dollars in his savings account 2 months after his initial deposit.
(D) Eddie has 5,120.72 dollars in his savings account, which yields 2 percent annual interest.

f(x)=5,000(1.012)t f(x)=5,000(1.012)^{t} \newlineThe function models f f , the amount of money in Eddie's savings account x x years after his initial deposit into the account. Which of the following statements is the best interpretation of the ordered pair (2,5120.72) (2,5120.72) ?\newlineChoose 11 answer:\newline(A) Eddie earned 55,120120.7272 dollars in interest from his savings account 22 years after his initial deposit.\newline(B) Eddie has 55,120120.7272 dollars in his savings account 22 years after his initial deposit.\newline(C) Eddie has 55,120120.7272 dollars in his savings account 22 months after his initial deposit.\newline(D) Eddie has 55,120120.7272 dollars in his savings account, which yields 22 percent annual interest.

Full solution

Q. f(x)=5,000(1.012)t f(x)=5,000(1.012)^{t} \newlineThe function models f f , the amount of money in Eddie's savings account x x years after his initial deposit into the account. Which of the following statements is the best interpretation of the ordered pair (2,5120.72) (2,5120.72) ?\newlineChoose 11 answer:\newline(A) Eddie earned 55,120120.7272 dollars in interest from his savings account 22 years after his initial deposit.\newline(B) Eddie has 55,120120.7272 dollars in his savings account 22 years after his initial deposit.\newline(C) Eddie has 55,120120.7272 dollars in his savings account 22 months after his initial deposit.\newline(D) Eddie has 55,120120.7272 dollars in his savings account, which yields 22 percent annual interest.
  1. Plug in value of t: Plug in the value of tt from the ordered pair into the function to check if it matches the amount given.\newlinef(2)=5000(1.012)2f(2) = 5000(1.012)^2
  2. Calculate (1.012)2(1.012)^2: Calculate the value of (1.012)2.(1.012)^2.\newline(1.012)2=1.024144(1.012)^2 = 1.024144
  3. Multiply by 11.024144024144: Multiply 50005000 by 1.0241441.024144 to find the amount in the account after 22 years.\newline5000×1.024144=5120.725000 \times 1.024144 = 5120.72
  4. Compare calculated amount: Compare the calculated amount with the amount given in the ordered pair. 5120.725120.72 matches the amount in the ordered pair (2,5120.72)(2,5120.72).
  5. Interpret ordered pair: Interpret the ordered pair (2,5120.72)(2,5120.72) based on the function and the calculation.\newlineThe ordered pair means that Eddie has 5120.725120.72 dollars in his savings account 22 years after his initial deposit.

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