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Solve the system of equations.\newliney=x2+40x20y = x^2 + 40x - 20\newliney=40x4y = 40x - 4\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)

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Q. Solve the system of equations.\newliney=x2+40x20y = x^2 + 40x - 20\newliney=40x4y = 40x - 4\newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(______,______)\newline(______,______)
  1. Set Equations Equal: We have the system of equations:\newliney=x2+40x20y = x^2 + 40x - 20\newliney=40x4y = 40x - 4\newlineTo find the intersection points, set the two equations equal to each other.\newlinex2+40x20=40x4x^2 + 40x - 20 = 40x - 4
  2. Simplify and Rearrange: Simplify the equation by subtracting 40x40x from both sides and adding 44 to both sides.\newlinex2+40x2040x+4=40x440x+4x^2 + 40x - 20 - 40x + 4 = 40x - 4 - 40x + 4\newlinex216=0x^2 - 16 = 0
  3. Solve Quadratic Equation: Solve the quadratic equation for xx.x216=0x^2 - 16 = 0Factor the left side of the equation.(x4)(x+4)=0(x - 4)(x + 4) = 0
  4. Factor and Solve: Set each factor equal to zero and solve for xx.(x4)=0 or (x+4)=0(x - 4) = 0 \text{ or } (x + 4) = 0x=4 or x=4x = 4 \text{ or } x = -4
  5. Find y-Values: Find the corresponding y-values for each x-value by substituting back into either of the original equations. We'll use y=40x4y = 40x - 4.\newlineFor x=4x = 4:\newliney=40(4)4y = 40(4) - 4\newliney=1604y = 160 - 4\newliney=156y = 156
  6. Coordinate Calculation: For x=4x = -4:y=40(4)4y = 40(-4) - 4y=1604y = -160 - 4y=164y = -164
  7. Coordinate Calculation: For x=4x = -4:y=40(4)4y = 40(-4) - 4y=1604y = -160 - 4y=164y = -164Write the coordinates in exact form.First Coordinate:(4,156)\text{First Coordinate}: (4, 156)Second Coordinate:(4,164)\text{Second Coordinate}: (-4, -164)

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