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f(t)=800(0.85)^(t)
The function models 
f, the value of a computer, in dollars, 
t years after its purchase. Which of the following statements is the best interpretation of the ordered pair 
(5,355) ?
Choose 1 answer:
(A) The value of the computer increases by 355 dollars 5 years after its purchase.
(B) The value of the computer decreases by 355 dollars 5 years after its purchase.
(C) The value of the computer is 355 dollars 5 years after its purchase.
(D) The value of the computer decreases by 355 dollars per year 5 years after its purchase.

f(t)=800(0.85)t f(t)=800(0.85)^{t} \newlineThe function models f f , the value of a computer, in dollars, t t years after its purchase. Which of the following statements is the best interpretation of the ordered pair (5,355) (5,355) ?\newlineChoose 11 answer:\newline(A) The value of the computer increases by 355355 dollars 55 years after its purchase.\newline(B) The value of the computer decreases by 355355 dollars 55 years after its purchase.\newline(C) The value of the computer is 355355 dollars 55 years after its purchase.\newline(D) The value of the computer decreases by 355355 dollars per year 55 years after its purchase.

Full solution

Q. f(t)=800(0.85)t f(t)=800(0.85)^{t} \newlineThe function models f f , the value of a computer, in dollars, t t years after its purchase. Which of the following statements is the best interpretation of the ordered pair (5,355) (5,355) ?\newlineChoose 11 answer:\newline(A) The value of the computer increases by 355355 dollars 55 years after its purchase.\newline(B) The value of the computer decreases by 355355 dollars 55 years after its purchase.\newline(C) The value of the computer is 355355 dollars 55 years after its purchase.\newline(D) The value of the computer decreases by 355355 dollars per year 55 years after its purchase.
  1. Plug in t=5t=5: Plug in t=5t=5 into the function to check if f(5)f(5) equals 355355.\newlinef(5)=800(0.85)5f(5) = 800(0.85)^{5}
  2. Calculate power of 00.8585: Calculate the value of 0.850.85 raised to the power of 55. \newline(0.85)50.4437053125(0.85)^{5} \approx 0.4437053125
  3. Multiply 800800 by 0.44370531250.4437053125: Multiply 800800 by 0.44370531250.4437053125 to find f(5)f(5).\newlinef(5)800×0.4437053125f(5) \approx 800 \times 0.4437053125
  4. Perform multiplication: Perform the multiplication to find the value of the computer after 55 years. f(5)800×0.4437053125355f(5) \approx 800 \times 0.4437053125 \approx 355

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