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Express 9x+19^{x+1} minus 32x3^{2x} as a single term in the form a(b2x)a(b^{2x}).

Full solution

Q. Express 9x+19^{x+1} minus 32x3^{2x} as a single term in the form a(b2x)a(b^{2x}).
  1. Identify base numbers: Identify the base numbers in the expression.\newline99 is 33 squared, so 9(x+1)9^{(x+1)} can be written as (32)(x+1)(3^2)^{(x+1)}.
  2. Apply power rule: Apply the power of a power rule to simplify (32)(x+1)(3^2)^{(x+1)}.\newline(32)(x+1)(3^2)^{(x+1)} becomes 32(x+1)3^{2(x+1)}.
  3. Distribute exponent: Distribute the exponent inside the parentheses. 32(x+1)3^{2(x+1)} becomes 32x+23^{2x+2}.
  4. Look at second term: Now, look at the second term 3(2x)3^{(2x)}.\newlineThis term is already in the correct form.
  5. Combine terms: Combine the two terms into a single expression. 3(2x+2)3(2x)3^{(2x+2)} - 3^{(2x)} cannot be combined as a single term in the form a(b(2x))a(b^{(2x)}) because the exponents are different.

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