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Equation for the approximate line of best fit : 
y=(6)/(7)x+2(2)/(7)
14) Predict the cost of 8 pounds of strawtoemes.

Graph prediction: 
qquad in 9
Equolion prodection 
:19414 show your work:


(6)/(7)*8+2(2)/(7)

Predict the cost of 14 pounds of strawberries.


Graph prediction : 
1//4.50
Equation prediction : 
$4.29 Show your work:


(6)/(7)*14+2(2)/(7)

What does the slope of the line of best fit mean in the context of the given situalion is the slope reasonable in this situgtion? 
qquad are about even above and below the slope. 
qquad

qquad

qquad

qquad What does the 
y-intercept of the line of best fit mean in the context of the given situation? Is the y-intercept reasonable in this situation? 
qquad

qquad
02015 lindsav Perme
wuw.lindsayperfo.com

Equation for the approximate line of best fit : y=67x+227 y=\frac{6}{7} x+2 \frac{2}{7} \newline1414) Predict the cost of 88 pounds of strawtoemes.\newline- Graph prediction: \qquad in 99\newline- Equolion prodection :19414 : 19414 show your work:\newline678+227 \frac{6}{7} \cdot 8+2 \frac{2}{7} \newline1515) Predict the cost of 1414 pounds of strawberries.\newline- Graph prediction : 1/4.50 1 / 4.50 \newline- Equation prediction : $4.29 \$ 4.29 Show your work:\newline6714+227 \frac{6}{7} \cdot 14+2 \frac{2}{7} \newline1616) What does the slope of the line of best fit mean in the context of the given situalion is the slope reasonable in this situgtion? \qquad are about even above and below the slope. \qquad \newline \qquad \newline \qquad \newline \qquad What does the \qquad 00-intercept of the line of best fit mean in the context of the given situation? Is the y-intercept reasonable in this situation? \qquad \newline \qquad \newline0201502015 lindsav Perme\newlinewuw.lindsayperfo.com

Full solution

Q. Equation for the approximate line of best fit : y=67x+227 y=\frac{6}{7} x+2 \frac{2}{7} \newline1414) Predict the cost of 88 pounds of strawtoemes.\newline- Graph prediction: \qquad in 99\newline- Equolion prodection :19414 : 19414 show your work:\newline678+227 \frac{6}{7} \cdot 8+2 \frac{2}{7} \newline1515) Predict the cost of 1414 pounds of strawberries.\newline- Graph prediction : 1/4.50 1 / 4.50 \newline- Equation prediction : $4.29 \$ 4.29 Show your work:\newline6714+227 \frac{6}{7} \cdot 14+2 \frac{2}{7} \newline1616) What does the slope of the line of best fit mean in the context of the given situalion is the slope reasonable in this situgtion? \qquad are about even above and below the slope. \qquad \newline \qquad \newline \qquad \newline \qquad What does the \qquad 00-intercept of the line of best fit mean in the context of the given situation? Is the y-intercept reasonable in this situation? \qquad \newline \qquad \newline0201502015 lindsav Perme\newlinewuw.lindsayperfo.com
  1. Calculation for 88 pounds: Calculation for 88 pounds: (67)×8+2(27)(\frac{6}{7}) \times 8 + 2(\frac{2}{7})
  2. Multiply by 88: First, multiply (67)(\frac{6}{7}) by 88: 67×8=487\frac{6}{7} \times 8 = \frac{48}{7}
  3. Calculate 2(27)2\left(\frac{2}{7}\right): Then, calculate 2(27):2×27=472\left(\frac{2}{7}\right): 2 \times \frac{2}{7} = \frac{4}{7}
  4. Add results: Add the two results together: 487+47=527\frac{48}{7} + \frac{4}{7} = \frac{52}{7}
  5. Convert to mixed number or decimal: Convert 527\frac{52}{7} to a mixed number or decimal: 52÷7=7.4285714285752 \div 7 = 7.42857142857, which rounds to $7.43\$7.43
  6. Calculation for 1414 pounds: Calculation for 1414 pounds: (67)×14+2(27)(\frac{6}{7}) \times 14 + 2(\frac{2}{7})
  7. Multiply by 1414: First, multiply (67)(\frac{6}{7}) by 1414: 67×14=847\frac{6}{7} \times 14 = \frac{84}{7}
  8. Calculate 2(27)2\left(\frac{2}{7}\right): Then, calculate 2(27):2×27=472\left(\frac{2}{7}\right): 2 \times \frac{2}{7} = \frac{4}{7}
  9. Add results: Add the two results together: 847+47=887\frac{84}{7} + \frac{4}{7} = \frac{88}{7}
  10. Convert to mixed number or decimal: Convert 887\frac{88}{7} to a mixed number or decimal: 88÷7=12.571428571488 \div 7 = 12.5714285714, which rounds to $12.57\$12.57
  11. Slope interpretation: The slope (67)(\frac{6}{7}) represents the rate of change in cost per pound of strawberries. It seems reasonable as it shows a gradual increase in cost with weight.
  12. Y-intercept interpretation: The y-intercept 2(27)2\left(\frac{2}{7}\right) represents the starting cost when no strawberries are purchased. It's reasonable if it aligns with the minimum cost to start buying strawberries.

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