Ejercicio 1.1) Enunciar el Teorema Fundamental de la Aritmética y utilizarlo para mostrar que 48 es el número natural más chico que admite exactamente 10 divisores positivos.
Q. Ejercicio 1.1) Enunciar el Teorema Fundamental de la Aritmética y utilizarlo para mostrar que 48 es el número natural más chico que admite exactamente 10 divisores positivos.
State Theorem: State the Fundamental Theorem of Arithmetic: Every integer greater than 1 can be uniquely factored into prime numbers.
Factor 48: Factor 48 into prime factors: 48=24×31.
Calculate Divisors: Calculate the number of divisors using the formula (a+1)(b+1)… where a,b,… are the exponents of the prime factors: (4+1)(1+1)=5×2=10 divisors.
Check Smallest Number: Check if 48 is the smallest number with 10 divisors: Test smaller numbers with the same number of divisors.
Realize Smallest Number: Realize that 32=25 has only 6 divisors, and 36=22×32 has 9 divisors. Since 48 is the next number with more divisors, it is the smallest with 10 divisors.
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