Ejercicio 1.1) Enunciar el Teorema Fundamental de la Aritmética y utilizarlo para mostrar que 48 es el número natural más chico que admite exactamente 10 divisores positivos.2) Hallar m∈Z tal que el coeficiente que multiplica a x5 en (mx3+x−2)10 es 8064 .
Q. Ejercicio 1.1) Enunciar el Teorema Fundamental de la Aritmética y utilizarlo para mostrar que 48 es el número natural más chico que admite exactamente 10 divisores positivos.2) Hallar m∈Z tal que el coeficiente que multiplica a x5 en (mx3+x−2)10 es 8064 .
State Fundamental Theorem of Arithmetic: State the Fundamental Theorem of Arithmetic and use it to show that 48 is the smallest natural number with exactly 10 positive divisors.The Fundamental Theorem of Arithmetic states that every integer greater than 1 can be represented uniquely as a product of prime numbers, up to the order of the factors.48=24×31The number of divisors is given by (4+1)(1+1)=10, which confirms that 48 has exactly 10 divisors.
Expand Binomial Theorem: Expand (mx3+x−2)10 using the binomial theorem to find the term containing x5. We need the term where the powers of x add up to 5, which is the term with x3 from mx3 raised to the 7th power and x−2 raised to the 3rd power. The binomial coefficient for this term is C(10,3).
Calculate Binomial Coefficient: Calculate the binomial coefficient C(10,3).C(10,3)=3!(10−3)!10!=3×2×110×9×8=120
Write Term with x5: Write down the term containing x5. The term is C(10,3)⋅(mx3)7⋅(x−2)3. Substitute the binomial coefficient: 120⋅m7⋅x3⋅7⋅x−6. Simplify the powers of x: 120⋅m7⋅x21−6=120⋅m7⋅x15.
Find Value of m: Find the value of m such that the coefficient of x5 is 8064. We need to equate the coefficient of x15 in the term to 8064, but we made a mistake in the previous step; we need the coefficient of x5, not x15.
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