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Use the following function rule to find f(1).
{:[f(x)=(x+12)^(2)],[f(1)=◻]:}

Use the following function rule to find f(1) f(1) .\newlinef(x)=(x+12)2f(1)= \begin{array}{l} f(x)=(x+12)^{2} \\ f(1)=\square \end{array}

Full solution

Q. Use the following function rule to find f(1) f(1) .\newlinef(x)=(x+12)2f(1)= \begin{array}{l} f(x)=(x+12)^{2} \\ f(1)=\square \end{array}
  1. Identify Function Rule: Identify the function rule and the value to substitute.\newlineThe function rule given is f(x)=(x+12)2f(x) = (x + 12)^2. We need to find the value of f(1)f(1) by substituting xx with 11.
  2. Substitute xx with 11: Substitute xx with 11 in the function rule.f(1)=(1+12)2f(1) = (1 + 12)^2
  3. Perform Addition: Perform the addition inside the parentheses.\newlinef(1)=(13)2f(1) = (13)^2
  4. Calculate Square: Calculate the square of 1313. \newlinef(1)=169f(1) = 169

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