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ehallpass Enter Game PIN - K... Formative pltw Tierra Del Sol Midd.l. Tierra D Requ xamine the triangle at right. Each part is a separate problem. Homework Help a. If m/_D=48^(@) and m/_F=117^(@), then what is m/_E ? b. Solve for x if m/_D=4x+2^(@),m/_F=7x-8^(@), and m/_E=4x+6^(@). Then calculate m/_D. c. If m/_D=m/_F=m/_E, what type of triangle is /_\FED ? ive the following systems of equations algebraically and then confirm your solutions by graphing. Homework Help

ehallpass\newlineEnter Game PIN - K...\newlineFormative\newlinepltw\newlineTierra Del Sol Midd.l.\newlineTierra D\newlineRequ\newlinexamine the triangle at right. Each part is a separate problem. Homework Help\newlinea. If m∠D=48∘ m \angle D=48^{\circ} and m∠F=117∘ m \angle F=117^{\circ} , then what is m∠E m \angle E ?\newlineb. Solve for x x if m∠D=4x+2∘,m∠F=7x−8∘ m \angle D=4 x+2^{\circ}, m \angle F=7 x-8^{\circ} , and m∠E=4x+6∘ m \angle E=4 x+6^{\circ} . Then calculate m∠D m \angle D .\newlinec. If m∠D=m∠F=m∠E m \angle D=m \angle F=m \angle E , what type of triangle is △FED \triangle F E D ?\newlineive the following systems of equations algebraically and then confirm your solutions by graphing. Homework Help

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Q. ehallpass\newlineEnter Game PIN - K...\newlineFormative\newlinepltw\newlineTierra Del Sol Midd.l.\newlineTierra D\newlineRequ\newlinexamine the triangle at right. Each part is a separate problem. Homework Help\newlinea. If m∠D=48∘ m \angle D=48^{\circ} and m∠F=117∘ m \angle F=117^{\circ} , then what is m∠E m \angle E ?\newlineb. Solve for x x if m∠D=4x+2∘,m∠F=7x−8∘ m \angle D=4 x+2^{\circ}, m \angle F=7 x-8^{\circ} , and m∠E=4x+6∘ m \angle E=4 x+6^{\circ} . Then calculate m∠D m \angle D .\newlinec. If m∠D=m∠F=m∠E m \angle D=m \angle F=m \angle E , what type of triangle is △FED \triangle F E D ?\newlineive the following systems of equations algebraically and then confirm your solutions by graphing. Homework Help
  1. Find Angle E: a. To find m/Em/_{E}, use the fact that the sum of angles in a triangle is 180180 degrees.\newlinem/D+m/F+m/E=180∘m/_{D} + m/_{F} + m/_{E} = 180^{\circ}\newline48∘+117∘+m/E=180∘48^{\circ} + 117^{\circ} + m/_{E} = 180^{\circ}\newlinem/E=180∘−48∘−117∘m/_{E} = 180^{\circ} - 48^{\circ} - 117^{\circ}\newlinem/E=15∘m/_{E} = 15^{\circ}
  2. Solve for x: b. To solve for x, set up the equation using the given angle expressions.\newline4x+2∘+7x−8∘+4x+6∘=180∘4x + 2^{\circ} + 7x - 8^{\circ} + 4x + 6^{\circ} = 180^{\circ}\newline15x=180∘−2∘+8∘−6∘15x = 180^{\circ} - 2^{\circ} + 8^{\circ} - 6^{\circ}\newline15x=180∘15x = 180^{\circ}\newlinex=180∘15x = \frac{180^{\circ}}{15}\newlinex=12x = 12

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