Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

each

/_A= 
qquad 
LA= 
qquad (answer in 
pi
TA 
= 
qquad 
TA= 
qquad
(answer in 
pi )
(3)

(10 pts)
Bonus Problems
( 
10pts )
#I
Given: 
LA=316.8 units 
^(2)
Find the side of the square base.

x=

qquad

TA=
(ansiver in real A
Given: 
LA=241.78 unit
Find 
r and 
T_(A)=
Square
#2
Bones Problem ( 10 pts)

#3
Length of corner edge 
qquad
base

A_("base ")=100 unirs 
^(2)

each\newlineA= \angle A= \qquad LA= L A= \qquad (answer in π \pi \newlineTA = = \qquad TA= T A= \qquad \newline(answer in π \pi )\newline(33)\newline \qquad 00\newlineBonus Problems\newline( \qquad 11 )\newline\#I\newlineGiven: \qquad 22 units \qquad 33\newlineFind the side of the square base.\newlinex= x= \newline \qquad \newlineTA= T A= \newline(ansiver in real A\newlineGiven: \qquad 66 unit\newlineFind \qquad 77 and \qquad 88\newlineSquare\newline\#22\newlineBones Problem ( 1010 pts)\newline \qquad 99\newlineLength of corner edge \qquad \newlinebase\newlineLA= L A= 11 unirs \qquad 33

Full solution

Q. each\newlineA= \angle A= \qquad LA= L A= \qquad (answer in π \pi \newlineTA = = \qquad TA= T A= \qquad \newline(answer in π \pi )\newline(33)\newline \qquad 00\newlineBonus Problems\newline( \qquad 11 )\newline\#I\newlineGiven: \qquad 22 units \qquad 33\newlineFind the side of the square base.\newlinex= x= \newline \qquad \newlineTA= T A= \newline(ansiver in real A\newlineGiven: \qquad 66 unit\newlineFind \qquad 77 and \qquad 88\newlineSquare\newline\#22\newlineBones Problem ( 1010 pts)\newline \qquad 99\newlineLength of corner edge \qquad \newlinebase\newlineLA= L A= 11 unirs \qquad 33
  1. Given Information: Given the lateral area LALA of a square-based pyramid is 316.8316.8 square units, we need to find the side length ss of the square base. The formula for the lateral area of a square-based pyramid is LA=4×(s×slant_height/2)LA = 4 \times (s \times \text{slant\_height} / 2), where slant_height\text{slant\_height} is the height from the base to the apex along the pyramid's side.
  2. Formula for Lateral Area: We don't have the slant height, but we can rearrange the formula to solve for the side length assuming the slant height is equal to the side length for simplicity (which is not generally true but let's assume for calculation). So, LA=4×(s×s/2)=2s2LA = 4 \times (s \times s / 2) = 2s^2.

More problems from Solve quadratic equations: word problems