each∠A=LA= (answer in πTA =TA=(answer in π )(3)0Bonus Problems( 1 )\#IGiven: 2 units 3Find the side of the square base.x=TA=(ansiver in real AGiven: 6 unitFind 7 and 8Square\#2Bones Problem ( 10 pts)9Length of corner edge baseLA=1 unirs 3
Q. each∠A=LA= (answer in πTA =TA=(answer in π )(3)0Bonus Problems( 1 )\#IGiven: 2 units 3Find the side of the square base.x=TA=(ansiver in real AGiven: 6 unitFind 7 and 8Square\#2Bones Problem ( 10 pts)9Length of corner edge baseLA=1 unirs 3
Given Information: Given the lateral area LA of a square-based pyramid is 316.8 square units, we need to find the side length s of the square base. The formula for the lateral area of a square-based pyramid is LA=4×(s×slant_height/2), where slant_height is the height from the base to the apex along the pyramid's side.
Formula for Lateral Area: We don't have the slant height, but we can rearrange the formula to solve for the side length assuming the slant height is equal to the side length for simplicity (which is not generally true but let's assume for calculation). So, LA=4×(s×s/2)=2s2.
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