Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

dydx=y1x3\frac{dy}{dx}=y^{-1}x^{-3}

Full solution

Q. dydx=y1x3\frac{dy}{dx}=y^{-1}x^{-3}
  1. Identify Function: Identify the function to differentiate.\newlineWe need to find the derivative of y=y1x3y = y^{-1}x^{-3} with respect to xx.
  2. Apply Product Rule: Apply the product rule for differentiation.\newlineThe product rule states that (uv)=uv+uv(uv)' = u'v + uv', where uu and vv are functions of xx.\newlineHere, u=y1u = y^{-1} and v=x3v = x^{-3}.
  3. Differentiate Functions: Differentiate each function.\newlineFor u=y1u = y^{-1}, the derivative u=1×y2×dydxu' = -1 \times y^{-2} \times \frac{dy}{dx} (using chain rule).\newlineFor v=x3v = x^{-3}, the derivative v=3x4v' = -3x^{-4} (using power rule).
  4. Substitute into Formula: Substitute back into the product rule formula.\newline(dydx)=(1×y2×dydx)×x3+y1×(3x4)(\frac{dy}{dx}) = (-1 \times y^{-2} \times \frac{dy}{dx}) \times x^{-3} + y^{-1} \times (-3x^{-4})

More problems from Composition of linear and quadratic functions: find a value