Direct Messages - SEQTA LeaAssessment Master - Exam Wiassess.scsa.wa.edu.au/engine/index.php/lms/indexSchool Curriculum and Standards AuthorityNumeracy(C) 0:19:34 / 0:50:0031751624Loaves of bread are sold in bags closed with plastic clips.Students at East Lake School collected 1 million of these clips.They want to estimate the total mass of the clips, in kilograms.Which rule will not give them a good estimation?41 of 45Question 32Question 33Question 34Question 35Question 36Count the number of clips in 10 grams of clips, then multiply by 100000 .Count the number of clips in 1 kilogram of clips, then divide 1 million by this number.Find the mass of 1 clip in grams, multiply by 1 million and then divide by 1000 .Find the mass of 20 clips in grams, divide by 1000 and then multiply by 50000 .Content copyright WA School Curriculum and Standards Authority 2024a)AssessmentCopyright ⊕ SoNET Systems Pty Ltd. 2024(.)Master
Q. Direct Messages - SEQTA LeaAssessment Master - Exam Wiassess.scsa.wa.edu.au/engine/index.php/lms/indexSchool Curriculum and Standards AuthorityNumeracy(C) 0:19:34 / 0:50:0031751624Loaves of bread are sold in bags closed with plastic clips.Students at East Lake School collected 1 million of these clips.They want to estimate the total mass of the clips, in kilograms.Which rule will not give them a good estimation?41 of 45Question 32Question 33Question 34Question 35Question 36Count the number of clips in 10 grams of clips, then multiply by 100000 .Count the number of clips in 1 kilogram of clips, then divide 1 million by this number.Find the mass of 1 clip in grams, multiply by 1 million and then divide by 1000 .Find the mass of 20 clips in grams, divide by 1000 and then multiply by 50000 .Content copyright WA School Curriculum and Standards Authority 2024a)AssessmentCopyright ⊕ SoNET Systems Pty Ltd. 2024(.)Master
Analyze Rule 1: Analyze the first rule: Count the number of clips in 10 grams of clips, then multiply by 100000. Calculation: If 10 grams contain X clips, then 1 million clips would weigh $(X \text{ clips}/\(10\) \text{ grams}) \times \(100000\) \times \(10\) \text{ grams} = X \times \(100000\) \text{ grams}.
Analyze Rule \(2\): Analyze the second rule: Count the number of clips in \(1\) kilogram of clips, then divide \(1\) million by this number.\(\newline\)Calculation: If \(1\) kilogram (\(1000\) grams) contains \(Y\) clips, then the mass of \(1\) million clips is \((1 \text{ million} / Y)\) kilograms.
Analyze Rule \(3\): Analyze the third rule: Find the mass of \(1\) clip in grams, multiply by \(1\) million and then divide by \(1000\). Calculation: If \(1\) clip weighs \(Z\) grams, then \(1\) million clips weigh \(Z \times 1\) million grams, which is \((Z \times 1\) million \(/ 1000)\) kilograms.
Analyze Rule \(4\): Analyze the fourth rule: Find the mass of \(20\) clips in grams, divide by \(1000\) and then multiply by \(50000\). Calculation: If \(20\) clips weigh \(W\) grams, then \(1\) clip weighs \(W/20\) grams. The mass of \(1\) million clips is \(((W/20) \times 1 \text{ million}) / 1000\) kilograms = \((W \times 50000) / 1000\) kilograms = \(1000\)\(0\) kilograms.
More problems from Solve one-step and two-step equations: word problems