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Determine the equation of the circle with radius sqrt138 and center (-5,0).

Determine the equation of the circle with radius 138 \sqrt{138} and center (−5,0) (-5,0) .

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Full solution

Q. Determine the equation of the circle with radius 138 \sqrt{138} and center (−5,0) (-5,0) .
  1. Identify values: Identify the values of hh, kk, and rr.h=−5h = -5k=0k = 0r=138r = \sqrt{138}
  2. Substitute values: Substitute −5-5 for hh, 00 for kk, and 138\sqrt{138} for rr in the standard form equation of a circle.\newline(x - (\(-5))^22 + (y - 00)^22 = (\sqrt{138138})^22
  3. Simplify equation: Simplify the equation. (x+5)2+y2=138 (x + 5)^2 + y^2 = 138

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