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Coronary bypass surgery: The Agency for Healthcare Research and Quality reported that 
60% of people who had coronary bypass surgery in a recent year were over the age of 65 , Fifteen coronary bypass patients are sampled. Round the answers to at least four decimal places.
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(a) What is the probability that exactly 10 of them are over the age of 65 ?
The probability that exactly 10 of them are over the age of 65 is 
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Coronary bypass surgery: The Agency for Healthcare Research and Quality reported that 60% 60 \% of people who had coronary bypass surgery in a recent year were over the age of 6565 , Fifteen coronary bypass patients are sampled. Round the answers to at least four decimal places.\newlinePart: 0/4 0 / 4 \newlinePart 11 of 44\newline(a) What is the probability that exactly 1010 of them are over the age of 6565 ?\newlineThe probability that exactly 1010 of them are over the age of 6565 is \square

Full solution

Q. Coronary bypass surgery: The Agency for Healthcare Research and Quality reported that 60% 60 \% of people who had coronary bypass surgery in a recent year were over the age of 6565 , Fifteen coronary bypass patients are sampled. Round the answers to at least four decimal places.\newlinePart: 0/4 0 / 4 \newlinePart 11 of 44\newline(a) What is the probability that exactly 1010 of them are over the age of 6565 ?\newlineThe probability that exactly 1010 of them are over the age of 6565 is \square
  1. Identify values: We're dealing with a binomial probability problem here. The formula for binomial probability is P(X=k)=(nk)pk(1p)nkP(X=k) = \binom{n}{k} \cdot p^k \cdot (1-p)^{n-k}, where nn is the number of trials, kk is the number of successes, pp is the probability of success on a single trial, and (nk)\binom{n}{k} is the binomial coefficient.
  2. Calculate binomial coefficient: First, let's identify the values we need: n=15n = 15 (the number of patients), k=10k = 10 (the number of patients we want to have had the surgery who are over 6565), and p=0.60p = 0.60 (the probability that a patient is over 6565).
  3. Calculate factorial values: Now, calculate the binomial coefficient (1510)15 \choose 10. This is equal to 15!10!(1510)!\frac{15!}{10! \cdot (15-10)!}.
  4. Divide factorial values: Calculating the factorial values, we get 15!=1,307,674,368,00015! = 1,307,674,368,000, 10!=3,628,80010! = 3,628,800, and 5!=1205! = 120.
  5. Simplify division: Now, divide 15!15! by 10!10! and 5!5! to get the binomial coefficient: (1510)=1,307,674,368,000(3,628,800×120)\binom{15}{10} = \frac{1,307,674,368,000}{(3,628,800 \times 120)}.
  6. Simplify division: Now, divide 15!15! by 10!10! and 5!5! to get the binomial coefficient: (1510)=1,307,674,368,000(3,628,800×120)\binom{15}{10} = \frac{1,307,674,368,000}{(3,628,800 \times 120)}.Simplify the division to get (1510)=3,003\binom{15}{10} = 3,003.

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