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Consider this matrix:

[[-9,-6],[0,2]]
Find the inverse of the matrix. Give exact values. Non-integers can be given as decimals or as simplified fractions.

Consider this matrix:\newline[9602] \left[\begin{array}{cc} -9 & -6 \\ 0 & 2 \end{array}\right] \newlineFind the inverse of the matrix. Give exact values. Non-integers can be given as decimals or as simplified fractions.

Full solution

Q. Consider this matrix:\newline[9602] \left[\begin{array}{cc} -9 & -6 \\ 0 & 2 \end{array}\right] \newlineFind the inverse of the matrix. Give exact values. Non-integers can be given as decimals or as simplified fractions.
  1. Calculate Determinant: To find the inverse of a 2×22 \times 2 matrix given by [[a,b],[c,d]][[a, b], [c, d]], we use the formula for the inverse of a 2×22 \times 2 matrix: 1adbc×[[d,b],[c,a]]\frac{1}{ad - bc} \times [[d, -b], [-c, a]]. First, we need to calculate the determinant of the matrix, which is adbcad - bc.
  2. Find Determinant: Calculate the determinant of the matrix [[9,6],[0,2]][[-9,-6],[0,2]]. The determinant is (9)(2)(0)(6)=180=18(-9)(2) - (0)(-6) = -18 - 0 = -18.
  3. Apply Inverse Formula: Since the determinant is not zero, the matrix has an inverse. Now, we apply the formula for the inverse of a 2×22 \times 2 matrix. The inverse matrix is 1(18)×[26 09]\frac{1}{(-18)} \times \left[\begin{array}{cc} 2 & 6 \ 0 & -9 \end{array}\right].
  4. Multiply by 1(18)\frac{1}{(-18)}: Multiply each element of the matrix by 1(18)\frac{1}{(-18)} to get the inverse matrix. The resulting matrix is [218618 0918]\left[\begin{array}{cc} -\frac{2}{18} & -\frac{6}{18} \ 0 & \frac{9}{18} \end{array}\right].
  5. Simplify Fractions: Simplify the fractions in the matrix to get the final inverse matrix. The simplified matrix is [1913 012]\left[\begin{array}{cc} \frac{1}{9} & -\frac{1}{3} \ 0 & -\frac{1}{2} \end{array}\right].

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