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ClassLink | Identity & Access MaI
Christ the King
https://www.ixl.com/m=4h/algebra-1/factor-polynomials
My IXL
Algebra 
1 > X. 9 Factor polynomials TAH
Factor completely.

4f^(2)+7f+3
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ClassLink | Identity \& Access MaI\newlineChrist the King\newlinehttps://www.ixl.com/m=44h/algebra1-1/factor-polynomials\newlineMy IXL\newlineAlgebra 1> 1> X. 99 Factor polynomials TAH\newlineFactor completely.\newline4f2+7f+3 4 f^{2}+7 f+3 \newlineSubmit

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Q. ClassLink | Identity \& Access MaI\newlineChrist the King\newlinehttps://www.ixl.com/m=44h/algebra1-1/factor-polynomials\newlineMy IXL\newlineAlgebra 1> 1> X. 99 Factor polynomials TAH\newlineFactor completely.\newline4f2+7f+3 4 f^{2}+7 f+3 \newlineSubmit
  1. Identify Common Factor: Look for a common factor in all terms of the polynomial 4f2+7f+34f^2 + 7f + 3. Check if there is a greatest common factor (GCF) that can be factored out. In this case, the terms 4f24f^2, 7f7f, and 33 do not have a common factor other than 11.
  2. Attempt Trinomial Factoring: Since there is no common factor, we will attempt to factor the trinomial into two binomials.\newlineThe general form of factoring a trinomial is (af+b)(cf+d)(af + b)(cf + d), where the product of acac equals the coefficient of f2f^2 (which is 44 in this case), and the product of bdbd equals the constant term (which is 33 in this case), and the sum of ad+bcad + bc equals the coefficient of ff (which is 77 in this case).
  3. Find Suitable Numbers: Find two numbers that multiply to 4×3=124 \times 3 = 12 and add up to 77. The numbers that satisfy these conditions are 33 and 44.
  4. Write Four-Term Expression: Write the trinomial as a four-term expression using the numbers found in Step 33.\newline4f2+4f+3f+34f^2 + 4f + 3f + 3
  5. Factor by Grouping: Group the terms into two pairs and factor by grouping.\newline(4f2+4f)+(3f+3)(4f^2 + 4f) + (3f + 3)\newlineFactor out the common factors from each group.\newline4f(f+1)+3(f+1)4f(f + 1) + 3(f + 1)
  6. Factor Common Binomial: Factor out the common binomial factor (f+1)(f + 1).\newline(4f+3)(f+1)(4f + 3)(f + 1)
  7. Verify Factored Form: Check the factored form by multiplying the binomials to see if we get the original polynomial.\newline(4f+3)(f+1)=4f2+4f+3f+3=4f2+7f+3(4f + 3)(f + 1) = 4f^2 + 4f + 3f + 3 = 4f^2 + 7f + 3\newlineThe factored form matches the original polynomial, so the factoring is correct.

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