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C_(2)quad5t-3=3t-5

$C_{2} \quad 5 t-3=3 t-5$

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Solve linear equations

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Q.

C_{2} \quad 5 t-3=3 t-5

Get $t$ terms together: First, let's get all the $t$ terms on one side by subtracting $3t$ from both sides. $\newline$ $5t - 3 - 3t = 3t - 5 - 3t$ $\newline$ $2t - 3 = -5$
Isolate $t$ : Now, we'll isolate $t$ by adding $3$ to both sides. $\newline$ $2t - 3 + 3 = -5 + 3$ $\newline$ $2t = -2$
Divide by $2$ : Finally, divide both sides by $2$ to solve for $t$ . $\frac{2t}{2} = \frac{-2}{2}$ $t = -1$

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