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blog.prepscholar.com/hardest-sat-math-questions get the answer (if you're stumped). No Calculator SAT Math Questions Question 1 C=(5)/(9)(F-32) The equation above shows how temperature F, measured in degrees Fahrenheit, relates to a temperature C, measured in degrees Celsius. Based on the equation, which of the following must be true? I. A temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of (5)/(9) degree Celsius. II. A temperature increase of 1 degree Celsius is equivalent to a temperature increase of 1.8 degrees Fahrenheit. III. A temperature increase of (5)/(9) degree Fahrenheit is equivalent to a temperature increase of 1 degree Celsius. Free SAT/ACT Tips to Boost Your Score Get EXCLUSIVE insider tips on how to ACE THE SAT and ACT for FREE! 100% Privacy. No spam ever. "I am absolutely overjoyed and cannot thank you enough for helping me!" A) I only B) II only C) III only D) I and II only ANSWER EXPLANATION: Think of the equation as an equation for a line

blog.prepscholar.com/hardest-sat-math-questions\newlineget the answer (if you're stumped).\newlineNo Calculator SAT Math Questions\newlineQuestion 11\newlineC=59(F−32) C=\frac{5}{9}(F-32) \newlineThe equation above shows how temperature F F , measured in degrees Fahrenheit, relates to a temperature C C , measured in degrees Celsius. Based on the equation, which of the following must be true?\newlineI. A temperature increase of 11 degree Fahrenheit is equivalent to a temperature increase of 59 \frac{5}{9} degree Celsius.\newlineII. A temperature increase of 11 degree Celsius is equivalent to a temperature increase of 11.88 degrees Fahrenheit.\newlineIII. A temperature increase of 59 \frac{5}{9} degree Fahrenheit is equivalent to a temperature increase of 11 degree Celsius.\newlineFree SAT/ACT Tips to Boost Your Score\newlineGet EXCLUSIVE insider tips on how to ACE THE SAT and ACT for FREE!\newline100% 100 \% Privacy. No spam ever.\newline

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Q. blog.prepscholar.com/hardest-sat-math-questions\newlineget the answer (if you're stumped).\newlineNo Calculator SAT Math Questions\newlineQuestion 11\newlineC=59(F−32) C=\frac{5}{9}(F-32) \newlineThe equation above shows how temperature F F , measured in degrees Fahrenheit, relates to a temperature C C , measured in degrees Celsius. Based on the equation, which of the following must be true?\newlineI. A temperature increase of 11 degree Fahrenheit is equivalent to a temperature increase of 59 \frac{5}{9} degree Celsius.\newlineII. A temperature increase of 11 degree Celsius is equivalent to a temperature increase of 11.88 degrees Fahrenheit.\newlineIII. A temperature increase of 59 \frac{5}{9} degree Fahrenheit is equivalent to a temperature increase of 11 degree Celsius.\newlineFree SAT/ACT Tips to Boost Your Score\newlineGet EXCLUSIVE insider tips on how to ACE THE SAT and ACT for FREE!\newline100% 100 \% Privacy. No spam ever.\newline
  1. Rewrite Equation: Rewrite the equation to make it easier to see the relationship between Fahrenheit and Celsius: C=(59)(F−32)C = \left(\frac{5}{9}\right)(F - 32).
  2. Check Statement I: To check statement I, increase FF by 11 degree and see how CC changes: C=(59)((F+1)−32)−(59)(F−32)C = \left(\frac{5}{9}\right)\left((F + 1) - 32\right) - \left(\frac{5}{9}\right)(F - 32).
  3. Simplify Change in C: Simplify the expression to find the change in C: ΔC=(59)(F+1−32)−(59)(F−32)=(59)(1)=59\Delta C = \left(\frac{5}{9}\right)(F + 1 - 32) - \left(\frac{5}{9}\right)(F - 32) = \left(\frac{5}{9}\right)(1) = \frac{5}{9} degrees Celsius.
  4. Statement I True: Statement I is true because an increase of 11 degree Fahrenheit is equivalent to an increase of 59\frac{5}{9} degree Celsius.
  5. Check Statement II: To check statement II, increase CC by 11 degree and see how FF changes: F=95C+32F = \frac{9}{5}C + 32. Now, F=95(C+1)+32F = \frac{9}{5}(C + 1) + 32.
  6. Simplify Change in F: Simplify the expression to find the change in F: ΔF=(95)(C+1)+32−((95)C+32)=(95)(1)=1.8\Delta F = \left(\frac{9}{5}\right)(C + 1) + 32 - \left(\left(\frac{9}{5}\right)C + 32\right) = \left(\frac{9}{5}\right)(1) = 1.8 degrees Fahrenheit.
  7. Statement II True: Statement II is true because an increase of 11 degree Celsius is equivalent to an increase of 1.81.8 degrees Fahrenheit.
  8. Check Statement III: To check statement III, increase FF by (5/9)(5/9) degree and see how CC changes: C=(59)((F+59)−32)C = \left(\frac{5}{9}\right)\left((F + \frac{5}{9}) - 32\right).
  9. Simplify Change in C: Simplify the expression to find the change in CC: ΔC=(59)(F+59−32)−(59)(F−32)=(59)(59)=2581\Delta C = \left(\frac{5}{9}\right)(F + \frac{5}{9} - 32) - \left(\frac{5}{9}\right)(F - 32) = \left(\frac{5}{9}\right)\left(\frac{5}{9}\right) = \frac{25}{81} degrees Celsius, which is not equal to 11 degree Celsius.
  10. Statement III False: Statement III is false because an increase of (5/9)(5/9) degree Fahrenheit is not equivalent to an increase of 11 degree Celsius.

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