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Bela started studying how the number of branches on her tree grows over time. Every 2.9 years, the number of branches increases by an additional 
83%, and can be modeled by a function, 
N, which depends on the amount of time, 
t (in years).
When Bela began the study, her tree had 60 branches.
Write a function that models the number of branches 
t years since Bela began studying her tree.

N(t)=◻

Bela started studying how the number of branches on her tree grows over time. Every 22.99 years, the number of branches increases by an additional 83% 83 \% , and can be modeled by a function, N N , which depends on the amount of time, t t (in years).\newlineWhen Bela began the study, her tree had 6060 branches.\newlineWrite a function that models the number of branches t t years since Bela began studying her tree.\newlineN(t)= N(t)=\square

Full solution

Q. Bela started studying how the number of branches on her tree grows over time. Every 22.99 years, the number of branches increases by an additional 83% 83 \% , and can be modeled by a function, N N , which depends on the amount of time, t t (in years).\newlineWhen Bela began the study, her tree had 6060 branches.\newlineWrite a function that models the number of branches t t years since Bela began studying her tree.\newlineN(t)= N(t)=\square
  1. Identify initial number and growth rate: Identify the initial number of branches and the growth rate.\newlineThe initial number of branches aa is given as 6060.\newlineThe growth rate rr is 83%83\%, which can be expressed as a decimal by dividing by 100100: r=83100=0.83r = \frac{83}{100} = 0.83.
  2. Determine growth factor: Determine the growth factor.\newlineSince the number of branches increases by 83%83\%, the growth factor (bb) is 11 plus the growth rate: b=1+rb = 1 + r.\newlineb=1+0.83b = 1 + 0.83\newlineb=1.83b = 1.83
  3. Write exponential function for number of branches: Write the function that models the number of branches.\newlineThe function N(t)N(t) that models the number of branches tt years since Bela began studying her tree is in the form of an exponential function: N(t)=a(b)tN(t) = a(b)^t.\newlineHowever, since the growth happens every 2.92.9 years, we need to adjust the exponent to reflect this. The exponent should be t2.9\frac{t}{2.9} to account for the growth period.\newlineN(t)=60(1.83)t2.9N(t) = 60(1.83)^{\frac{t}{2.9}}

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