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Enzo is studying the black bear population at a large national park.
He finds that the relationship between the elapsed time 
t, in years, since the beginning of the study, and the black bear population 
B(t), in the park is modeled by the following function.

B(t)=2500*2^(0.01 t)
According to the model, what will the black bear population be at that national park in 25 years? Round your answer, if necessary, to the nearest whole number.
bears

Enzo is studying the black bear population at a large national park.\newlineHe finds that the relationship between the elapsed time t t , in years, since the beginning of the study, and the black bear population B(t) B(t) , in the park is modeled by the following function.\newlineB(t)=250020.01t B(t)=2500 \cdot 2^{0.01 t} \newlineAccording to the model, what will the black bear population be at that national park in 2525 years? Round your answer, if necessary, to the nearest whole number.\newlinebears

Full solution

Q. Enzo is studying the black bear population at a large national park.\newlineHe finds that the relationship between the elapsed time t t , in years, since the beginning of the study, and the black bear population B(t) B(t) , in the park is modeled by the following function.\newlineB(t)=250020.01t B(t)=2500 \cdot 2^{0.01 t} \newlineAccording to the model, what will the black bear population be at that national park in 2525 years? Round your answer, if necessary, to the nearest whole number.\newlinebears
  1. Identify values and function: Identify the values of t and the function B(t).\newlineElapsed time (t) = 2525 years\newlineThe function that models the black bear population is B(t) = 25002500 \times 22^{(00.0101t)}.
  2. Substitute value into function: Substitute the value of tt into the function B(t)B(t).\newlineB(25)=2500×2(0.01×25)B(25) = 2500 \times 2^{(0.01 \times 25)}
  3. Calculate the exponent: Calculate the exponent.\newline0.01×25=0.250.01 \times 25 = 0.25
  4. Calculate 22 raised to the power: Calculate 20.252^{0.25}.\newline20.251.1892071152^{0.25} \approx 1.189207115
  5. Multiply result by 25002500: Multiply the result by 25002500 to find B(25)B(25).\newlineB(25)=2500×1.189207115B(25) = 2500 \times 1.189207115\newlineB(25)2973.0177875B(25) \approx 2973.0177875
  6. Round result to nearest whole number: Round the result to the nearest whole number. B(25)2973B(25) \approx 2973 bears

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