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Answer the questions below about the quadratic function.

g(x)=2x^(2)-16 x+35
Does the function have a minimum or maximum value?
Minimum
Maximum
What is the function's minimum or maximum value?

◻
Where does the minimum or maximum value occur?

x=

Answer the questions below about the quadratic function.\newlineg(x)=2x216x+35 g(x)=2 x^{2}-16 x+35 \newlineDoes the function have a minimum or maximum value?\newlineMinimum\newlineMaximum\newlineWhat is the function's minimum or maximum value?\newline \square \newlineWhere does the minimum or maximum value occur?\newlinex= x=

Full solution

Q. Answer the questions below about the quadratic function.\newlineg(x)=2x216x+35 g(x)=2 x^{2}-16 x+35 \newlineDoes the function have a minimum or maximum value?\newlineMinimum\newlineMaximum\newlineWhat is the function's minimum or maximum value?\newline \square \newlineWhere does the minimum or maximum value occur?\newlinex= x=
  1. Identify Function Type: Identify the type of function and determine if it has a minimum or maximum value.\newlineSince the coefficient of x2x^2 in g(x)=2x216x+35g(x) = 2x^2 - 16x + 35 is positive (22), the parabola opens upwards, indicating a minimum value.
  2. Convert to Vertex Form: Convert the quadratic equation to vertex form to find the minimum value and the x-coordinate of the vertex.\newlineComplete the square for the quadratic term:\newline11. Factor out the coefficient of x2x^2 from the first two terms: g(x)=2(x28x)+35g(x) = 2(x^2 - 8x) + 35.\newline22. Calculate (82)2=16\left(\frac{-8}{2}\right)^2 = 16.\newline33. Add and subtract 1616 inside the bracket: g(x)=2(x28x+1616)+35g(x) = 2(x^2 - 8x + 16 - 16) + 35.\newline44. Simplify inside the bracket: g(x)=2((x4)216)+35g(x) = 2((x - 4)^2 - 16) + 35.\newline55. Distribute and combine like terms: g(x)=2(x4)232+35=2(x4)2+3g(x) = 2(x - 4)^2 - 32 + 35 = 2(x - 4)^2 + 3.
  3. Find Minimum Value: Identify the minimum value and the x-coordinate where it occurs.\newlineThe vertex form of the equation is g(x)=2(x4)2+3g(x) = 2(x - 4)^2 + 3. The vertex is (4,3)(4, 3).\newline- The x-coordinate of the vertex (where the minimum occurs) is x=4x = 4.\newline- The minimum value of the function is 33.

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