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An elevator descends into a mine shaft at the rate of
6m//min. If the descent starts
(a)
a÷0 is not defined from
10m above the ground level, how long will it take to reach
-350m.

$7$ . An elevator descends into a mine shaft at the rate of $6 \mathrm{~m} / \mathrm{min}$ . If the descent starts $\newline$ (a) $a \div 0$ is not defined from $10 \mathrm{~m}$ above the ground level, how long will it take to reach $-350 \mathrm{~m}$ .

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Find derivatives of radical functions

Full solution

Q.

7

. An elevator descends into a mine shaft at the rate of

6 \mathrm{~m} / \mathrm{min}

. If the descent starts

\newline

(a)

a \div 0

is not defined from

10 \mathrm{~m}

above the ground level, how long will it take to reach

-350 \mathrm{~m}

.

Calculate total distance: Calculate the total distance the elevator needs to descend. $\newline$ Starting from $10\,\text{m}$ above ground level to $-350\,\text{m}$ is a total distance of $10\,\text{m} - (-350\,\text{m})$ .
Perform subtraction: Perform the subtraction to find the total distance. $\newline$ Total distance = $10\,\text{m} + 350\,\text{m} = 360\,\text{m}$ .
Determine descent time: Determine the time it takes to descend $360\,\text{m}$ at a rate of $6\,\text{m/min}$ . $\newline$ Time = Total distance / Rate of descent.
Perform division: Perform the division to find the time. $\newline$ Time = $360\,\text{m} / 6\,\text{m/min} = 60$ minutes.

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