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An arctic cold front caused the temperature to drop a total of 
20^(@)C. The temperature was dropping at a rate of 
10^(@)C per hour. The temperature dropped an equal amount each hour.
The following equation describes this situation.

-20÷-10=2
What does 2 tell us?
Choose 1 answer:
(A) The temperature dropped 
20^(@)C in 2 hours.
(B) The temperature dropped 
10^(@)C in 2 hours.
(C) The temperature is dropping at a rate of 
2^(@)C per hour.

An arctic cold front caused the temperature to drop a total of 20C 20^{\circ} \mathrm{C} . The temperature was dropping at a rate of 10C 10^{\circ} \mathrm{C} per hour. The temperature dropped an equal amount each hour.\newlineThe following equation describes this situation.\newline20÷10=2 -20 \div-10=2 \newlineWhat does 22 tell us?\newlineChoose 11 answer:\newline(A) The temperature dropped 20C 20^{\circ} \mathrm{C} in 22 hours.\newline(B) The temperature dropped 10C 10^{\circ} \mathrm{C} in 22 hours.\newline(C) The temperature is dropping at a rate of 2C 2^{\circ} \mathrm{C} per hour.

Full solution

Q. An arctic cold front caused the temperature to drop a total of 20C 20^{\circ} \mathrm{C} . The temperature was dropping at a rate of 10C 10^{\circ} \mathrm{C} per hour. The temperature dropped an equal amount each hour.\newlineThe following equation describes this situation.\newline20÷10=2 -20 \div-10=2 \newlineWhat does 22 tell us?\newlineChoose 11 answer:\newline(A) The temperature dropped 20C 20^{\circ} \mathrm{C} in 22 hours.\newline(B) The temperature dropped 10C 10^{\circ} \mathrm{C} in 22 hours.\newline(C) The temperature is dropping at a rate of 2C 2^{\circ} \mathrm{C} per hour.
  1. Calculate Division: The equation given is 20÷10=2-20 \div -10 = 2. Calculate the division to find out what the 22 represents. 20÷10=2-20 \div -10 = 2.
  2. Interpret Result: Interpret the result of the division in the context of the temperature drop. The 22 represents the number of hours it took for the temperature to drop by 20C20\,^\circ\mathrm{C}, since the rate was 10C10\,^\circ\mathrm{C} per hour.

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