Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

An airplane takes off 200200 yards in front of a 180180 yard building.\newlineFind the angle of elevation for the plane so it does not hit the building.

Full solution

Q. An airplane takes off 200200 yards in front of a 180180 yard building.\newlineFind the angle of elevation for the plane so it does not hit the building.
  1. Identify Known Values: Identify the known values and the problem to be solved.\newlineWe know the following:\newline- The distance from the plane's takeoff point to the building is 200200 yards.\newline- The height of the building is 180180 yards.\newlineWe need to find the angle of elevation that the plane must have to clear the building without hitting it.
  2. Visualize Problem: Visualize the problem as a right triangle. The building forms a vertical line (height), the distance from the takeoff point to the building forms the horizontal line (base), and the path of the plane forms the hypotenuse. The angle of elevation is the angle between the base and the hypotenuse.
  3. Use Trigonometry: Use trigonometry to find the angle of elevation.\newlineThe tangent of the angle of elevation θ\theta is the ratio of the opposite side (height of the building) to the adjacent side (distance from the takeoff point to the building).\newlineSo, tan(θ)=oppositeadjacent=height of the buildingdistance from takeoff point to building\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{\text{height of the building}}{\text{distance from takeoff point to building}}.
  4. Calculate Tangent: Calculate the tangent of the angle of elevation.\newlinetan(θ)=180yards200yards\tan(\theta) = \frac{180 \, \text{yards}}{200 \, \text{yards}}\newlinetan(θ)=0.9\tan(\theta) = 0.9
  5. Find Angle: Find the angle of elevation using the arctangent function. \newlineθ=arctan(0.9)\theta = \text{arctan}(0.9)\newlineUse a calculator to find the angle in degrees.
  6. Calculate with Calculator: Calculate the angle using a calculator.\newlineθarctan(0.9)41.99\theta \approx \arctan(0.9) \approx 41.99 degrees\newlineThe angle of elevation should be approximately 41.9941.99 degrees for the plane to clear the building.

More problems from Understanding integers