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Alice and Candice went shopping with the same amount of money at first. After Alice spent $480 and Candice spent $620, Alice had twice as much money as Candice. How much money did they have altogether at first?

11. Alice and Candice went shopping with the same amount of money at first. After Alice spent $480 \$ 480 and Candice spent $620 \$ 620 , Alice had twice as much money as Candice. How much money did they have altogether at first?

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Q. 11. Alice and Candice went shopping with the same amount of money at first. After Alice spent $480 \$ 480 and Candice spent $620 \$ 620 , Alice had twice as much money as Candice. How much money did they have altogether at first?
  1. Set Initial Amounts: Let's call the amount of money Alice and Candice each had at first xx. After spending, Alice has x−$480x - \$480 and Candice has x−$620x - \$620. We're told Alice has twice as much as Candice after spending, so we can write the equation: x−$480=2(x−$620)x - \$480 = 2(x - \$620).
  2. Distribute 22: Now, let's solve for xx. First, distribute the 22 on the right side of the equation: x−$480=2x−$1240x - \$480 = 2x - \$1240.
  3. Move Terms: Next, we'll move all the xx terms to one side and the numbers to the other side. So, subtract xx from both sides to get: −$480=x−$1240-\$480 = x - \$1240.

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