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A triangle has vertices on a coordinate grid at
U(-6,-4),V(1,-4), and
W(-6,7). What is the length, in units, of
bar(UV) ?
Answer: units

A triangle has vertices on a coordinate grid at $U(-6,-4), V(1,-4)$ , and $W(-6,7)$ . What is the length, in units, of $\overline{U V}$ ? $\newline$ Answer: $\square$ units

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Calculate quartiles and interquartile range

Full solution

Q. A triangle has vertices on a coordinate grid at

U(-6,-4), V(1,-4)

, and

W(-6,7)

. What is the length, in units, of

\overline{U V}

?

\newline

Answer:

\square

units

Identify Points U and V: Identify the coordinates of points U and V. $\newline$ Point U has coordinates $(-6, -4)$ and point V has coordinates $(1, -4)$ .
Calculate Length of bar(UV): Use the distance formula to calculate the length of bar(UV). The distance formula is $d = \sqrt{[(x_2 - x_1)^2 + (y_2 - y_1)^2]}$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are the coordinates of two points. For bar(UV), we have $(x_1, y_1) = (-6, -4)$ and $(x_2, y_2) = (1, -4)$ .
Plug Coordinates into Formula: Plug the coordinates into the distance formula. $\newline$ $d = \sqrt{[(1 - (-6))^2 + (-4 - (-4))^2]}$ $\newline$ $d = \sqrt{[(1 + 6)^2 + (0)^2]}$ $\newline$ $d = \sqrt{[7^2 + 0^2]}$ $\newline$ $d = \sqrt{[49 + 0]}$ $\newline$ $d = \sqrt{[49]}$ $\newline$ $d = 7$

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