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A town has a population of 
5.56 ×10^(4) and grows at a rate of 
4% every year. Which equation represents the town's population after 7 years?

P=(5.56 ×10^(4))(1+0.04)^(7)

P=(5.56 ×10^(4))(1+0.04)(1+0.04)(1+0.04)(1+0.04)

P=(5.56 ×10^(4))(0.04)^(7)

P=(5.56 ×10^(4))(1-0.04)^(7)

A town has a population of 5.56×104 5.56 \times 10^{4} and grows at a rate of 4% 4 \% every year. Which equation represents the town's population after 77 years?\newlineP=(5.56×104)(1+0.04)7 P=\left(5.56 \times 10^{4}\right)(1+0.04)^{7} \newlineP=(5.56×104)(1+0.04)(1+0.04)(1+0.04)(1+0.04) P=\left(5.56 \times 10^{4}\right)(1+0.04)(1+0.04)(1+0.04)(1+0.04) \newlineP=(5.56×104)(0.04)7 P=\left(5.56 \times 10^{4}\right)(0.04)^{7} \newlineP=(5.56×104)(10.04)7 P=\left(5.56 \times 10^{4}\right)(1-0.04)^{7}

Full solution

Q. A town has a population of 5.56×104 5.56 \times 10^{4} and grows at a rate of 4% 4 \% every year. Which equation represents the town's population after 77 years?\newlineP=(5.56×104)(1+0.04)7 P=\left(5.56 \times 10^{4}\right)(1+0.04)^{7} \newlineP=(5.56×104)(1+0.04)(1+0.04)(1+0.04)(1+0.04) P=\left(5.56 \times 10^{4}\right)(1+0.04)(1+0.04)(1+0.04)(1+0.04) \newlineP=(5.56×104)(0.04)7 P=\left(5.56 \times 10^{4}\right)(0.04)^{7} \newlineP=(5.56×104)(10.04)7 P=\left(5.56 \times 10^{4}\right)(1-0.04)^{7}
  1. Exponential Growth Formula: To find the population after 77 years with a growth rate of 4%4\% per year, we use the formula for exponential growth: P=P0(1+r)tP = P_0(1 + r)^t, where P0P_0 is the initial population, rr is the growth rate, and tt is the time in years.
  2. Given Values: The initial population P0P_0 is given as 5.56×1045.56 \times 10^4. The growth rate rr is 4%4\%, which is 0.040.04 in decimal form. The time tt is 77 years.
  3. Substitute Values: Substitute the given values into the exponential growth formula: P=(5.56×104)(1+0.04)7P = (5.56 \times 10^4)(1 + 0.04)^7.
  4. Correct Representation: The equation P=(5.56×104)(1+0.04)7P = (5.56 \times 10^4)(1 + 0.04)^7 correctly represents the population after 77 years, considering a 4%4\% annual growth rate compounded once per year.
  5. Evaluation of Options: The other options can be evaluated for correctness:\newline- P=(5.56×104)(1+0.04)(1+0.04)(1+0.04)(1+0.04)P = (5.56 \times 10^4)(1 + 0.04)(1 + 0.04)(1 + 0.04)(1 + 0.04) does not correctly apply the compound interest formula, as it only multiplies the growth factor 44 times instead of 77.\newline- P=(5.56×104)(0.04)7P = (5.56 \times 10^4)(0.04)^7 incorrectly raises the growth rate to the power of 77 instead of applying it as a percentage increase.\newline- P=(5.56×104)(10.04)7P = (5.56 \times 10^4)(1 - 0.04)^7 incorrectly assumes a decrease by 4%4\% per year instead of an increase.

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