Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

a) Sign of the leading coefficient\newlineb) Vertex\newlinec) Axis of symmetry\newlined) Intervals where \newlineff is increasing and where \newlineff is decreasi\newlinef) Domain and range\newlineFor the toolbar, press ALT+F1010 (PC) or ALT+FN+F1010 (Mac).\newlineB I \newlineS_ Paragraph \newlinevv Arial

Full solution

Q. a) Sign of the leading coefficient\newlineb) Vertex\newlinec) Axis of symmetry\newlined) Intervals where \newlineff is increasing and where \newlineff is decreasi\newlinef) Domain and range\newlineFor the toolbar, press ALT+F1010 (PC) or ALT+FN+F1010 (Mac).\newlineB I \newlineS_ Paragraph \newlinevv Arial
  1. Sign of Leading Coefficient: a) Sign of the leading coefficient: The leading coefficient is the number in front of the highest power of xx, which is 6-6 in this case. Since it's negative, the parabola opens downwards.
  2. Vertex: b) Vertex: The vertex form of a quadratic function is f(x)=a(xh)2+kf(x) = a(x - h)^2 + k, where (h,k)(h, k) is the vertex. For f(x)=6(x7)2+2f(x) = -6(x - 7)^2 + 2, the vertex is (7,2)(7, 2).
  3. Axis of Symmetry: c) Axis of symmetry: The axis of symmetry is a vertical line that passes through the vertex. For the given function, the axis of symmetry is x=7x = 7.
  4. Increasing and Decreasing Intervals: d) Intervals where ff is increasing and where ff is decreasing: Since the parabola opens downwards (a<0a < 0), f(x)f(x) is increasing to the left of the vertex and decreasing to the right of the vertex. So, ff is increasing on (,7)(-\infty, 7) and decreasing on (7,)(7, \infty).
  5. Domain and Range: e) Domain and range: The domain of any quadratic function is all real numbers, so the domain of f(x)f(x) is (,)(-\infty, \infty). The range is limited by the vertex since it's the highest point on the graph. The range is (,2](-\infty, 2].

More problems from Reflections of functions