Q. GIVEN: FS⊥HA, FS⊥LG, FLSH is a parallelogram PROVE: △LGS≅△HAF
Identify Given and Prove: Identify the given information and what needs to be proven.Given: FS is perpendicular to HA, FS is perpendicular to LG, and FLSH is a parallelogram.Prove: Triangle LGS is similar to triangle HAF.
Parallelogram Properties: Use the properties of a parallelogram to determine the relationship between opposite sides and angles.In parallelogram FLSH, opposite sides are equal and opposite angles are equal. Therefore, FL=HS and LS=FH. Also, angle FLS is equal to angle HSF.
Perpendicular Lines: Use the given perpendicular lines to determine right angles.Since FS is perpendicular to HA and LG, angles FSH and FSL are right angles (90 degrees).
Additional Right Angles: Determine additional right angles based on the properties of a parallelogram.Since FLSH is a parallelogram and angle FLS is equal to angle HSF, angle HSF is also a right angle. Therefore, angle HAF is a right angle because it is vertical to angle HSF.
Compare Angles: Compare the angles in triangles LGS and HAF. Both triangles have a right angle: angle LGS in triangle LGS and angle HAF in triangle HAF. Since FLSH is a parallelogram, angle LSF is equal to angle HSF. Therefore, angle LGS is equal to angle HAF.
AA Similarity Postulate: Use the Angle-Angle (AA) similarity postulate to prove the triangles are similar.Since two angles of triangle LGS are equal to two angles of triangle HAF (angle LGS is equal to angle HAF and both have a right angle), by the AA postulate, the triangles are similar.