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A polynomial $p$ has zeros when $x=-2, x=\frac{1}{3}$, and $x=3$.$\newline$What could be the equation of $p$ ?$\newline$Choose $1$ answer:$\newline$(A) $p(x)=(x+2)(x+3)(3 x+1)$$\newline$(B) $p(x)=(x+2)(x+3)(3 x-1)$$\newline$(C) $p(x)=(x+2)(x-3)(3 x-1)$$\newline$(D) $p(x)=(x-2)(x+3)(3 x+1)$