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A line with a slope of −9-9 passes through the points (2,0)(2,0) and (3,j)(3,j). What is the value of jj?\newlinej = ____

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Q. A line with a slope of −9-9 passes through the points (2,0)(2,0) and (3,j)(3,j). What is the value of jj?\newlinej = ____
  1. Understand slope concept: Understand the concept of slope. The slope of a line is the ratio of the change in the yy-coordinate to the change in the xx-coordinate between two points on the line. The formula for slope (mm) is given by: m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1} Here, we are given the slope (mm) as −9-9, and we have two points (2,0)(2,0) and (3,j)(3,j).
  2. Plug in values: Plug in the known values into the slope formula.\newlineWe know the slope mm is −9-9, and we have the points (2,0)(2,0) and (3,j)(3,j). Let's denote (2,0)(2,0) as (x1,y1)(x_1, y_1) and (3,j)(3,j) as (x2,y2)(x_2, y_2). Plugging these into the slope formula gives us:\newline−9=j−03−2-9 = \frac{j - 0}{3 - 2}
  3. Simplify equation: Simplify the equation to solve for jj.−9=j1-9 = \frac{j}{1}Multiplying both sides by 11 gives us:j=−9×1j = -9 \times 1j=−9j = -9

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