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A line with a slope of 88 passes through the points (−7,c)(-7,c) and (−8,−6)(-8,-6). What is the value of cc?\newlinec = ____

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Full solution

Q. A line with a slope of 88 passes through the points (−7,c)(-7,c) and (−8,−6)(-8,-6). What is the value of cc?\newlinec = ____
  1. Understand slope concept: Understand the concept of slope. The slope of a line is the ratio of the change in the yy-coordinate to the change in the xx-coordinate between two points on the line. The formula for slope (mm) when given two points ((x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2)) is: m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}
  2. Apply slope formula: Apply the slope formula to the given points and slope.\newlineWe know the slope mm is 88, and we have the points (−7,c)(-7, c) and (−8,−6)(-8, -6). Let's plug these into the slope formula:\newline8=c−(−6)−7−(−8)8 = \frac{c - (-6)}{-7 - (-8)}
  3. Simplify equation and solve: Simplify the equation and solve for cc.8=c+6−7+88 = \frac{c + 6}{-7 + 8}8=c+618 = \frac{c + 6}{1}Now, multiply both sides by 11 to isolate c+6c + 6 on one side:8×1=c+68 \times 1 = c + 68=c+68 = c + 6
  4. Subtract to find cc: Subtract 66 from both sides to solve for cc.8−6=c8 - 6 = c2=c2 = c

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