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A line with a slope of −5-5 passes through the points (−3,w)(-3,w) and (−2,−9)(-2,-9). What is the value of ww?\newlinew=___w = \_\_\_

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Q. A line with a slope of −5-5 passes through the points (−3,w)(-3,w) and (−2,−9)(-2,-9). What is the value of ww?\newlinew=___w = \_\_\_
  1. Set up slope equation: Step 11: Use the slope formula to set up the equation. The slope formula is (y2−y1)/(x2−x1)(y_2 - y_1) / (x_2 - x_1). Here, (x1,y1)=(−3,w)(x_1, y_1) = (-3, w) and (x2,y2)=(−2,−9)(x_2, y_2) = (-2, -9).\newlineSlope = (−9−w)/(−2+3)(-9 - w) / (-2 + 3)
  2. Set slope equal to −5-5: Step 22: Since the slope of the line is given as −5-5, set the expression equal to −5-5.\newline−5=−9−w1-5 = \frac{-9 - w}{1}\newlineMultiply both sides by 11 to simplify:\newline−5=−9−w-5 = -9 - w
  3. Solve for w: Step 33: Solve for w. Add 99 to both sides of the equation.\newline−5+9=−9+9−w-5 + 9 = -9 + 9 - w\newline4=−w4 = -w
  4. Final solution for w: Step 44: Multiply both sides by −1-1 to solve for ww.w=−4w = -4

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