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A line with a slope of −3-3 passes through the points (1,−10)(1,-10) and (−1,w)(-1,w). What is the value of ww?\newlinew=___w = \_\_\_

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Full solution

Q. A line with a slope of −3-3 passes through the points (1,−10)(1,-10) and (−1,w)(-1,w). What is the value of ww?\newlinew=___w = \_\_\_
  1. Identify formula for slope: Identify the formula for the slope between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2), which is y2−y1x2−x1\frac{y_2 - y_1}{x_2 - x_1}. Here, we know the slope is −3-3, and we have the points (1,−10)(1, -10) and (−1,w)(-1, w).
  2. Plug in known values: Plug in the known values into the slope formula: −3=(w−(−10))/(−1−1)-3 = (w - (-10)) / (-1 - 1). Simplify the equation: −3=(w+10)/−2-3 = (w + 10) / -2.
  3. Solve for w: Solve for w: Multiply both sides by −2-2 to get 6=w+106 = w + 10.
  4. Subtract to find ww: Subtract 1010 from both sides to find ww: 6−10=w6 - 10 = w, w=−4w = -4.

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