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A line with a slope of 22 passes through the points (−8,−6)(-8,-6) and (−9,p)(-9,p). What is the value of pp?\newlinep=___p = \_\_\_

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Q. A line with a slope of 22 passes through the points (−8,−6)(-8,-6) and (−9,p)(-9,p). What is the value of pp?\newlinep=___p = \_\_\_
  1. Understand slope concept: Understand the concept of slope. The slope of a line is the ratio of the change in the yy-coordinate to the change in the xx-coordinate between two points on the line. The formula for slope (mm) is: m=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1} Since we know the slope of the line is 22, we can set up the equation using the given points (−8,−6(-8, -6) and (−9,p(-9, p).
  2. Plug values into formula: Plug the known values into the slope formula.\newlineUsing the points (−8,−6)(-8, -6) and (−9,p)(-9, p), we have:\newline2=p−(−6)−9−(−8)2 = \frac{p - (-6)}{-9 - (-8)}\newlineThis simplifies to:\newline2=p+6−9+82 = \frac{p + 6}{-9 + 8}
  3. Solve for pp: Solve for pp.\newlineNow we solve the equation:\newline2=(p+6)(−1)2 = \frac{(p + 6)}{(-1)}\newlineMultiplying both sides by −1-1 gives us:\newline−2=p+6-2 = p + 6\newlineSubtracting 66 from both sides gives us:\newlinep=−2−6p = -2 - 6\newlinep=−8p = -8

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