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A line that includes the points (6,1)(-6,-1) and (5,h)(-5,h) has a slope of 7-7. What is the value of hh?\newlineh=___h = \_\_\_

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Q. A line that includes the points (6,1)(-6,-1) and (5,h)(-5,h) has a slope of 7-7. What is the value of hh?\newlineh=___h = \_\_\_
  1. Identify Points and Slope: Identify the points and slope given in the problem. Points: (6,1)(-6, -1) and (5,h)(-5, h). Slope: 7-7. Use the slope formula: Slope=y2y1x2x1\text{Slope} = \frac{y_2 - y_1}{x_2 - x_1}.
  2. Use Slope Formula: Plug in the values into the slope formula. 7=h(1)5(6)-7 = \frac{h - (-1)}{-5 - (-6)}. Simplify the equation. 7=h+15+6-7 = \frac{h + 1}{-5 + 6}.
  3. Simplify Equation: Simplify further. 7=(h+1)1-7 = \frac{(h + 1)}{-1}. Multiply both sides by 1-1 to isolate h+1h + 1. 7=h+17 = h + 1.
  4. Solve for h: Solve for h. Subtract 11 from both sides. 71=h7 - 1 = h. h=6h = 6.

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