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A line that includes the points (−5,−5)(-5,-5) and (−6,h)(-6,h) has a slope of −7-7. What is the value of hh?\newlineh=___h = \_\_\_

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Q. A line that includes the points (−5,−5)(-5,-5) and (−6,h)(-6,h) has a slope of −7-7. What is the value of hh?\newlineh=___h = \_\_\_
  1. Understand the formula: Understand the formula for the slope of a line.\newlineThe slope of a line is calculated using the formula (change in y)/(change in x)(\text{change in } y) / (\text{change in } x) between two points on the line.
  2. Apply the slope formula: Apply the slope formula to the given points and slope.\newlineWe have the points (−5,−5)(-5,-5) and (−6,h)(-6,h) and the slope −7-7. Let's denote the first point as (x1,y1)(x_1, y_1) and the second point as (x2,y2)(x_2, y_2). The slope mm is given by:\newlinem=y2−y1x2−x1m = \frac{y_2 - y_1}{x_2 - x_1}\newlineWe can plug in the given values:\newline−7=h−(−5)−6−(−5)-7 = \frac{h - (-5)}{-6 - (-5)}
  3. Simplify and solve: Simplify the equation and solve for hh.−7=(h+5)(−1)-7 = \frac{(h + 5)}{(-1)}Now, multiply both sides by −1-1 to isolate (h+5)(h + 5):7=h+57 = h + 5
  4. Subtract to find hh: Subtract 55 from both sides to find the value of hh.7−5=h7 - 5 = hh=2h = 2

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