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A line that includes the points (−1,j)(-1,j) and (0,−2)(0,-2) has a slope of −9-9. What is the value of jj?\newlinej=j = ____

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Q. A line that includes the points (−1,j)(-1,j) and (0,−2)(0,-2) has a slope of −9-9. What is the value of jj?\newlinej=j = ____
  1. Identify Points and Slope: Identify the given points and the slope.\newlineWe have the points (−1,j)(-1, j) and (0,−2)(0, -2) and the slope of the line is −9-9.\newlineWe will use the slope formula which is y2−y1x2−x1=slope\frac{y_2 - y_1}{x_2 - x_1} = \text{slope}.
  2. Plug Values into Formula: Plug the values into the slope formula.\newline−9=(−2−j)/(0−(−1))-9 = (-2 - j) / (0 - (-1))\newlineSimplify the denominator.\newline−9=(−2−j)/1-9 = (-2 - j) / 1
  3. Solve for j: Solve for j.\newlineMultiply both sides by 11 to isolate the numerator.\newline−9×1=(−2−j)-9 \times 1 = (-2 - j)\newline−9=−2−j-9 = -2 - j
  4. Add 22 to Solve: Add 22 to both sides to solve for jj.−9+2=−2−j+2-9 + 2 = -2 - j + 2−7=−j-7 = -j
  5. Multiply by −1-1: Multiply both sides by −1-1 to get the value of jj.−7×−1=−j×−1-7 \times -1 = -j \times -17=j7 = j

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