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A line has a slope of 88 and includes the points (−1,9)(-1,9) and (−2,p)(-2,p). What is the value of pp?\newlinep=___p = \_\_\_

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Full solution

Q. A line has a slope of 88 and includes the points (−1,9)(-1,9) and (−2,p)(-2,p). What is the value of pp?\newlinep=___p = \_\_\_
  1. Use slope formula: Use the slope formula: Slope = (y2−y1)/(x2−x1)(y_2 - y_1) / (x_2 - x_1). Here, the slope is 88, and the points are (−1,9)(-1, 9) and (−2,p)(-2, p).\newlineCalculation: 8=(p−9)/(−2+1)8 = (p - 9) / (-2 + 1)
  2. Calculate slope: Simplify the denominator and solve for pp.\newlineCalculation: 8=p−9−18 = \frac{p - 9}{-1}
  3. Isolate pp: Multiply both sides by −1-1 to isolate p−9p - 9.\newlineCalculation: −8=p−9-8 = p - 9
  4. Solve for pp: Add 99 to both sides to solve for pp.\newlineCalculation: p=1p = 1

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