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A line has a slope of −10-10 and includes the points (−2,d)(-2,d) and (−1,−4)(-1,-4). What is the value of dd?\newlined = ____

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Q. A line has a slope of −10-10 and includes the points (−2,d)(-2,d) and (−1,−4)(-1,-4). What is the value of dd?\newlined = ____
  1. Identify Points and Slope: Identify the given points and the slope.\newlinePoints: (−2,d)(-2, d) and (−1,−4)(-1, -4)\newlineSlope: −10-10\newlineUse the slope formula to set up the equation.\newlineSlope =y2−y1x2−x1= \frac{y_2 - y_1}{x_2 - x_1}\newline−10=−4−d−1−(−2)-10 = \frac{-4 - d}{-1 - (-2)}
  2. Set Up Slope Equation: Simplify the denominator of the slope equation.\newline−10=−4−d−1+2-10 = \frac{-4 - d}{-1 + 2}\newline−10=−4−d1-10 = \frac{-4 - d}{1}
  3. Simplify Denominator: Since the denominator is 11, we can multiply both sides by 11 to isolate the numerator.\newline−10×1=(−4−d)×1-10 \times 1 = (-4 - d) \times 1\newline−10=−4−d-10 = -4 - d
  4. Isolate Numerator: Solve for dd by adding 44 to both sides of the equation.\newline−10+4=−4−d+4-10 + 4 = -4 - d + 4\newline−6=−d-6 = -d
  5. Solve for d: Multiply both sides by −1-1 to solve for d.\newline−1×−6=−1×−d-1 \times -6 = -1 \times -d\newline6=d6 = d

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