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A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t)=64 t-16t^(2). After how long will it reach its maximum height? Do not round your answer.

A ball is thrown vertically upward. After t t seconds, its height h h (in feet) is given by the function h(t)=64t−16t2 h(t)=64 t-16 t^{2} . After how long will it reach its maximum height?\newlineDo not round your answer.

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Q. A ball is thrown vertically upward. After t t seconds, its height h h (in feet) is given by the function h(t)=64t−16t2 h(t)=64 t-16 t^{2} . After how long will it reach its maximum height?\newlineDo not round your answer.
  1. Identify values of aa, bb, cc: Identify the values of aa, bb, and cc in the quadratic equation h(t)=64t−16t2h(t) = 64t - 16t^2.\newlineHere, a=−16a = -16, b=64b = 64, and c=0c = 0.
  2. Calculate time for maximum height: Calculate the time at which the ball reaches maximum height using the formula t=−b2at = -\frac{b}{2a}.\newlineSubstitute a=−16a = -16 and b=64b = 64 into the formula.\newlinet=−642∗(−16)t = -\frac{64}{2*(-16)}\newlinet=6432t = \frac{64}{32}\newlinet=2t = 2.

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