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The equation 
s=(t+3)^(2)(t+2)(t+1)(t)(t-1) is graphed on the 
st-plane. What is the product of the unique 
t-intercepts of the graph?

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The equation s=(t+3)2(t+2)(t+1)(t)(t1) s=(t+3)^{2}(t+2)(t+1)(t)(t-1) is graphed on the st s t -plane. What is the product of the unique t t -intercepts of the graph?\newline \square

Full solution

Q. The equation s=(t+3)2(t+2)(t+1)(t)(t1) s=(t+3)^{2}(t+2)(t+1)(t)(t-1) is graphed on the st s t -plane. What is the product of the unique t t -intercepts of the graph?\newline \square
  1. Identify t-intercepts: Identify the t-intercepts of the graph.\newlineThe t-intercepts occur when s=0s = 0. To find the t-intercepts, we set the equation equal to zero and solve for tt.\newline0=(t+3)2(t+2)(t+1)(t)(t1)0 = (t+3)^{2}(t+2)(t+1)(t)(t-1)\newlineThe t-intercepts are the solutions to this equation.
  2. Find unique solutions for tt: Find the unique solutions for tt.\newlineThe equation is already factored, so we can see the solutions directly from the factors:\newlinet+3=0t+3 = 0 \Rightarrow t=3t = -3 (this root is squared, but it still counts as one unique intercept)\newlinet+2=0t+2 = 0 \Rightarrow t=2t = -2\newlinet+1=0t+1 = 0 \Rightarrow t=1t = -1\newlinet=0t = 0 \newlinet1=0t-1 = 0 \Rightarrow t=1t = 1\newlineThese are the unique tt-intercepts of the graph.
  3. Calculate product of t-intercepts: Calculate the product of the unique t-intercepts.\newlineThe product of the t-intercepts is found by multiplying them together:\newlineProduct = (3)×(2)×(1)×(0)×(1)(-3) \times (-2) \times (-1) \times (0) \times (1)
  4. Simplify the product: Simplify the product.\newlineSince one of the factors is 00, the product of the tt-intercepts is 00.\newlineProduct = 00

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