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The common ratio of a geometric series is 3 and the sum of the first 8 terms is 3280 .
What is the first term of the series?

The common ratio of a geometric series is 33 and the sum of the first 88 terms is 32803280 .\newlineWhat is the first term of the series?

Full solution

Q. The common ratio of a geometric series is 33 and the sum of the first 88 terms is 32803280 .\newlineWhat is the first term of the series?
  1. Geometric Series Formula: The sum of the first nn terms of a geometric series can be found using the formula Sn=a(1rn)(1r)S_n = \frac{a(1 - r^n)}{(1 - r)}, where SnS_n is the sum of the first nn terms, aa is the first term, rr is the common ratio, and nn is the number of terms.\newlineIn this case, we know that S8=3280S_8 = 3280, r=3r = 3, and n=8n = 8. We need to find the value of aa.
  2. Plug in Known Values: Let's plug the known values into the sum formula for a geometric series:\newline3280=a(138)/(13)3280 = a(1 - 3^8) / (1 - 3).
  3. Calculate Exponent: Calculate the value of 383^8 and subtract it from 11: \newline38=65613^8 = 6561, \newline138=16561=65601 - 3^8 = 1 - 6561 = -6560.
  4. Calculate Denominator: Now, calculate the denominator of the fraction: 13=21 - 3 = -2.
  5. Substitute Values: Substitute the calculated values into the sum formula:\newline3280=a(6560)/(2)3280 = a(-6560) / (-2).
  6. Simplify Equation: Simplify the right side of the equation by dividing 6560-6560 by 2-2:a(6560)(2)=a×3280.\frac{a(-6560)}{(-2)} = a \times 3280.
  7. Solve for a: Now, solve for a by dividing both sides of the equation by 32803280: \newlinea=32803280,a = \frac{3280}{3280},\newlinea=1.a = 1.

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