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Solve for
x.
Enter the solutions from least to greatest.

x^(2)+7=43
lesser
x=
greater
x=

Solve for $x$ . Enter the solutions from least to greatest. $\newline$ $x^{2}+7=43$ $\newline$ lesser $x=$ $\newline$ greater $x=$

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Solve a quadratic equation using square roots

Full solution

Q. Solve for

x

. Enter the solutions from least to greatest.

\newline

x^{2}+7=43

\newline

lesser

x=

\newline

greater

x=

Isolate $x^2$ term: Subtract $7$ from both sides of the equation to isolate the $x^2$ term. $\newline$ $x^2 + 7 = 43$ $\newline$ $x^2 + 7 - 7 = 43 - 7$ $\newline$ $x^2 = 36$
Take square root: Take the square root of both sides of the equation to solve for $x$ . Remember that taking the square root of a number yields two solutions: one positive and one negative. $\newline$ $\sqrt{x^2} = \pm\sqrt{36}$ $\newline$ $x = \pm6$
Identify lesser and greater values of x: Identify the lesser and greater values of x. $\newline$ lesser x = $-6$ $\newline$ greater x = $6$

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