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Welcome to Bytelearn!
Let’s check out your problem:
Solve for
m
m
m
.
\newline
−
7
+
4
m
+
10
=
15
−
2
m
m
=
□
\begin{array}{l} -7+4 m+10=15-2 m \\ m=\square \end{array}
−
7
+
4
m
+
10
=
15
−
2
m
m
=
□
View step-by-step help
Home
Math Problems
Algebra 1
Solve linear equations with variables on both sides
Full solution
Q.
Solve for
m
m
m
.
\newline
−
7
+
4
m
+
10
=
15
−
2
m
m
=
□
\begin{array}{l} -7+4 m+10=15-2 m \\ m=\square \end{array}
−
7
+
4
m
+
10
=
15
−
2
m
m
=
□
Combine like terms:
Combine like terms on the left side of the equation.
\newline
−
7
+
4
m
+
10
=
15
−
2
m
-7 + 4m + 10 = 15 - 2m
−
7
+
4
m
+
10
=
15
−
2
m
\newline
(
4
m
+
3
)
=
15
−
2
m
(4m + 3) = 15 - 2m
(
4
m
+
3
)
=
15
−
2
m
Move variable and constant terms:
Move the variable terms to one side and the constant terms to the other side.
\newline
4
m
+
3
+
2
m
=
15
−
2
m
+
2
m
4m + 3 + 2m = 15 - 2m + 2m
4
m
+
3
+
2
m
=
15
−
2
m
+
2
m
\newline
6
m
+
3
=
15
6m + 3 = 15
6
m
+
3
=
15
Isolate the variable term:
Subtract
3
3
3
from both sides to isolate the variable term.
\newline
6
m
+
3
−
3
=
15
−
3
6m + 3 - 3 = 15 - 3
6
m
+
3
−
3
=
15
−
3
\newline
6
m
=
12
6m = 12
6
m
=
12
Solve for m:
Divide both sides by
6
6
6
to solve for m.
\newline
6
m
6
=
12
6
\frac{6m}{6} = \frac{12}{6}
6
6
m
=
6
12
\newline
m
=
2
m = 2
m
=
2
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