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Find the zeros of the function. Enter the solutions from least to greatest. f(x)=(x-1)^(2)-36 lesser x= greater x=

Find the zeros of the function. Enter the solutions from least to greatest.\newlinef(x)=(x−1)2−36f(x)=(x-1)^{2}-36\newlinelesser x=x= greater x=x=

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Full solution

Q. Find the zeros of the function. Enter the solutions from least to greatest.\newlinef(x)=(x−1)2−36f(x)=(x-1)^{2}-36\newlinelesser x=x= greater x=x=
  1. Find the zeros: Set the function equal to zero to find the zeros.\newlinef(x)=(x−1)2−36=0f(x) = (x - 1)^2 - 36 = 0
  2. Solve the equation: Solve the equation (x−1)2−36=0(x - 1)^2 - 36 = 0 by moving 3636 to the other side.\newline(x−1)2=36(x - 1)^2 = 36
  3. Take the square root: Take the square root of both sides to solve for xx.(x−1)2=±36\sqrt{(x - 1)^2} = \pm\sqrt{36}x−1=±6x - 1 = \pm6
  4. Solve for x: Solve for x by adding 11 to both sides of the equations.\newlinex=1+6x = 1 + 6 and x=1−6x = 1 - 6\newlinex=7x = 7 and x=−5x = -5

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