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9-3÷(1)/(3)+1=

$9-3\div\left(\frac{1}{3}\right)+1$ =

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Add three or more integers

Full solution

Q.

9-3\div\left(\frac{1}{3}\right)+1

=

Identify Order of Operations: Identify the order of operations to be used for the calculation. According to the order of operations (PEMDAS/BODMAS), we should first perform any calculations inside parentheses, then division, followed by addition and subtraction from left to right.
Perform Division Calculation: Since there are no calculations to perform inside the parentheses, we move on to the division. We have $3 \div (1/3)$ . To divide by a fraction, we multiply by its reciprocal. The reciprocal of $(1/3)$ is $3$ . So, we have $3 \times 3$ .
Multiply Result: Perform the multiplication from the previous step. We have $3 \times 3$ which equals $9$ .
Replace Division in Expression: Replace the division with the result from Step $3$ in the original expression. The new expression is $9 - 9 + 1$ .
Perform Subtraction: Perform the subtraction and addition from left to right. First, we do $9 - 9$ which equals $0$ .
Add Result: Now add the result from Step $5$ to $1$ . We have $0 + 1$ which equals $1$ .

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