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Math Problems
Grade 6
Add three or more integers
18
×
[
7
+
(
−
3
)
]
=
[
18
×
7
]
+
[
18
×
(
−
3
)
]
18\times[7+(-3)]=[18\times7]+[18\times(-3)]
18
×
[
7
+
(
−
3
)]
=
[
18
×
7
]
+
[
18
×
(
−
3
)]
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8
+
2
(
2
+
2
)
=
?
8+2(2+2)=?
8
+
2
(
2
+
2
)
=
?
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6
+
[
7
÷
(
7
×
1
)
]
=
8
6+[7 \div (7\times1)]=8
6
+
[
7
÷
(
7
×
1
)]
=
8
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1
+
7
−
10
1 + 7 - 10
1
+
7
−
10
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43
−
2
x
=
7
−
9
x
43-2 x=7-9 x
43
−
2
x
=
7
−
9
x
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b
=
09
+
21
b=09+21
b
=
09
+
21
(
1
1
1
)
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9
s
2
+
6
s
+
1
=
0
9s^2 + 6s + 1 = 0
9
s
2
+
6
s
+
1
=
0
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Find the value of
w
w
w
.
\newline
15
−
w
6
=
22
15-\frac{w}{6}=22
15
−
6
w
=
22
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4
+
1
/
1
+
1
/
1
(
−
0
)
/
(
−
2
)
+
1
+
2
/
2
+
1
/
1
(
−
0
)
/
(
−
3
)
×
6
+
22
4 + 1 / 1+1 / 1(-0) / (−2)+1+2 / 2+1 / 1(-0)/ (−3)\times6+22
4
+
1/1
+
1/1
(
−
0
)
/
(
−2
)
+
1
+
2/2
+
1/1
(
−
0
)
/
(
−3
)
×
6
+
22
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7
+
6
+
5
×
7
7+6+5\times 7
7
+
6
+
5
×
7
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6
+
8
+
1
+
6
6+8+1+6
6
+
8
+
1
+
6
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36
−
4
+
7
−
812
+
17
=
0
36-4+7-812+17=0
36
−
4
+
7
−
812
+
17
=
0
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What value of
x
x
x
satisfies the equation
3
(
2
+
x
)
+
7
=
−
11
3(2 + x) + 7 = -11
3
(
2
+
x
)
+
7
=
−
11
.
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10
2
+
5
−
7
\frac{10}{2}+5-7
2
10
+
5
−
7
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6
÷
2
(
1
+
2
6 \div 2(1+2
6
÷
2
(
1
+
2
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Nilai
x
,
y
,
z
x, y, z
x
,
y
,
z
dan
w
w
w
yang memenuhi
\newline
[
3
x
0
,
5
y
2
z
ω
]
=
[
x
y
+
1
5
z
+
1
]
+
[
5
2
+
y
0
,
25
z
4
]
\left[\begin{array}{cc} 3 x & 0,5 y \\ 2 z & \omega \end{array}\right]=\left[\begin{array}{ll} x & y+1 \\ 5 & z+1 \end{array}\right]+\left[\begin{array}{ll} 5 & 2+y \\ 0,25 z & 4 \end{array}\right]
[
3
x
2
z
0
,
5
y
ω
]
=
[
x
5
y
+
1
z
+
1
]
+
[
5
0
,
25
z
2
+
y
4
]
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6
+
1
\begin{array}{r}6 \\ +1 \\ \hline\end{array}
6
+
1
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Simplify the expression.
\newline
1
+
8
+
10
−
8
1 + 8 + 10 - 8
1
+
8
+
10
−
8
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Simplify the expression.
\newline
9
−
3
÷
1
3
+
1
=
?
9-3÷\frac{1}{3}+1=?
9
−
3
÷
3
1
+
1
=
?
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1
+
6
1+6
1
+
6
=
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1
+
7
−
10
1 + 7 - 10
1
+
7
−
10
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Evaluate:
1
+
7
−
10
1 + 7 - 10
1
+
7
−
10
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1
+
7
−
10
×
54
1 + 7 - 10 \times 54
1
+
7
−
10
×
54
=
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1
+
6
+
8
1+ 6+ 8
1
+
6
+
8
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x
3
+
2
x
2
+
3
x
+
4
=
0
x^3+2x^2+3x+4=0
x
3
+
2
x
2
+
3
x
+
4
=
0
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3
+
6
−
9
+
12
−
89
×
9
3+6-9+12-89\times9
3
+
6
−
9
+
12
−
89
×
9
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10
+
20
+
30
=
?
10+20+30 = ?
10
+
20
+
30
=
?
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402
+
376
=
?
402+376=?
402
+
376
=
?
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9
−
3
÷
(
1
3
)
+
1
9-3\div\left(\frac{1}{3}\right)+1
9
−
3
÷
(
3
1
)
+
1
=
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6
÷
2
(
1
+
2
)
6 \div 2(1+2)
6
÷
2
(
1
+
2
)
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