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6
x
289
(
15
−
2
)
6x289(15-2)
6
x
289
(
15
−
2
)
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Math Problems
Algebra 2
Evaluate logarithms using properties
Full solution
Q.
6
x
289
(
15
−
2
)
6x289(15-2)
6
x
289
(
15
−
2
)
Simplify Expression:
First, we need to simplify the expression inside the parentheses.
\newline
Calculate
15
−
2
15 - 2
15
−
2
.
\newline
15
−
2
=
13
15 - 2 = 13
15
−
2
=
13
Calculate Product:
Now, we have the simplified expression
6
x
289
x
13
6x289x13
6
x
289
x
13
. Next, we need to multiply
289
289
289
by
13
13
13
.
289
×
13
=
3757
289 \times 13 = 3757
289
×
13
=
3757
Final Result:
With the product of
289
289
289
and
13
13
13
found, we now multiply this result by
6
6
6
.
\newline
Calculate
6
×
3757
6 \times 3757
6
×
3757
.
\newline
6
×
3757
=
22542
6 \times 3757 = 22542
6
×
3757
=
22542
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log
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729
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\newline
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\newline
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\newline
log
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Question
Which property of logarithms does this equation demonstrate?
\newline
log
3
3
+
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6
=
log
3
18
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\newline
Choices:
\newline
(A)
Product Property
\text{Product Property}
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\newline
(B)
Power Property
\text{Power Property}
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\newline
(C)
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\text{Quotient Property}
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Expand the logarithm. Assume all expressions exist and are well-defined.
\newline
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\newline
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Expand the logarithm. Assume all expressions exist and are well-defined.
\newline
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\newline
log
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Expand the logarithm. Assume all expressions exist and are well-defined.
\newline
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\newline
log
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