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Math Problems
Algebra 2
Evaluate logarithms using properties
ext{Log}_{
5
5
5
} rac{
1
1
1
}{
4
4
4
} ext{ if } ext{log}_{
5
5
5
}
4
4
4
ext{ is } .
861
861
861
ext{ and } ext{log}_{
5
5
5
}
9
9
9
ext{ is }
1
1
1
.
365
365
365
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log
7
(
5
)
\log_7(5)
lo
g
7
(
5
)
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3
3
3
,
382
382
382
.
1677
1677
1677
What place is the selected digit in?
\newline
What is the value of the selected digit?
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what is
log
10
\log_{10}
lo
g
10
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6
x
289
(
15
−
2
)
6x289(15-2)
6
x
289
(
15
−
2
)
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Condense the logarithm
\newline
y
log
c
+
z
log
q
y \log c+z \log q
y
lo
g
c
+
z
lo
g
q
\newline
Answer:
log
(
□
)
\log (\square)
lo
g
(
□
)
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What is the value of
log
100
?
\log 100 ?
lo
g
100
?
\newline
Answer:
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What is the value of
log
10
\log 10
lo
g
10
?
\newline
Answer:
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log
1
3
81
=
\log _{\frac{1}{3}} 81=
lo
g
3
1
81
=
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log
25
1
5
=
\log _{25} \frac{1}{5}=
lo
g
25
5
1
=
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log
4
1
2
=
\log _{4} \frac{1}{2}=
lo
g
4
2
1
=
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log
64
1
4
=
\log _{64} \frac{1}{4}=
lo
g
64
4
1
=
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log
8
1
32
=
\log _{8} \frac{1}{32}=
lo
g
8
32
1
=
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log
3
1
27
=
\log _{3} \frac{1}{27}=
lo
g
3
27
1
=
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log
6
1
36
=
\log _{6} \frac{1}{36}=
lo
g
6
36
1
=
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log
2
64
=
\log _{2} 64=
lo
g
2
64
=
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Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
2
log
(
3
)
2 \log (3)
2
lo
g
(
3
)
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log
6
216
=
\log _{6} 216=
lo
g
6
216
=
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Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
log
(
5
)
+
log
(
4
)
\log (5)+\log (4)
lo
g
(
5
)
+
lo
g
(
4
)
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Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
log
(
4
)
+
log
(
3
)
\log (4)+\log (3)
lo
g
(
4
)
+
lo
g
(
3
)
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Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
log
(
3
)
+
log
(
2
)
\log (3)+\log (2)
lo
g
(
3
)
+
lo
g
(
2
)
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log
2
1
64
=
\log _{2} \frac{1}{64}=
lo
g
2
64
1
=
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log
81
1
3
=
\log _{81} \frac{1}{3}=
lo
g
81
3
1
=
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log
25
1
125
=
\log _{25} \frac{1}{125}=
lo
g
25
125
1
=
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log
27
1
3
=
\log _{27} \frac{1}{3}=
lo
g
27
3
1
=
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log
5
3125
=
\log _{5} 3125=
lo
g
5
3125
=
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log
9
729
=
\log _{9} 729=
lo
g
9
729
=
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log
81
1
27
=
\log _{81} \frac{1}{27}=
lo
g
81
27
1
=
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log
2
1024
=
\log _{2} 1024=
lo
g
2
1024
=
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log
3
81
=
\log _{3} 81=
lo
g
3
81
=
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log
6
36
=
\log _{6} 36=
lo
g
6
36
=
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log
3
729
=
\log _{3} 729=
lo
g
3
729
=
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Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
4
log
(
3
)
4 \log (3)
4
lo
g
(
3
)
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Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
3
log
(
4
)
3 \log (4)
3
lo
g
(
4
)
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Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
log
(
12
)
−
log
(
3
)
\log (12)-\log (3)
lo
g
(
12
)
−
lo
g
(
3
)
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Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
4
log
(
5
)
4 \log (5)
4
lo
g
(
5
)
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Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
log
(
15
)
−
log
(
3
)
\log (15)-\log (3)
lo
g
(
15
)
−
lo
g
(
3
)
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Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
2
log
(
5
)
2 \log (5)
2
lo
g
(
5
)
Get tutor help
Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
2
log
(
2
)
2 \log (2)
2
lo
g
(
2
)
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Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
2
log
(
4
)
2 \log (4)
2
lo
g
(
4
)
Get tutor help
Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
log
(
20
)
−
log
(
4
)
\log (20)-\log (4)
lo
g
(
20
)
−
lo
g
(
4
)
Get tutor help
Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
3
log
(
5
)
3 \log (5)
3
lo
g
(
5
)
Get tutor help
Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
log
(
8
)
−
log
(
2
)
\log (8)-\log (2)
lo
g
(
8
)
−
lo
g
(
2
)
Get tutor help
Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
3
log
(
2
)
3 \log (2)
3
lo
g
(
2
)
Get tutor help
Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
5
log
(
2
)
5 \log (2)
5
lo
g
(
2
)
Get tutor help
Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
log
(
3
)
+
log
(
4
)
\log (3)+\log (4)
lo
g
(
3
)
+
lo
g
(
4
)
Get tutor help
Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
log
(
10
)
−
log
(
2
)
\log (10)-\log (2)
lo
g
(
10
)
−
lo
g
(
2
)
Get tutor help
Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
log
(
2
)
+
log
(
4
)
\log (2)+\log (4)
lo
g
(
2
)
+
lo
g
(
4
)
Get tutor help
Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
log
(
3
)
+
log
(
5
)
\log (3)+\log (5)
lo
g
(
3
)
+
lo
g
(
5
)
Get tutor help
Rewrite the following in the form
log
(
c
)
\log (c)
lo
g
(
c
)
.
\newline
log
(
6
)
−
log
(
2
)
\log (6)-\log (2)
lo
g
(
6
)
−
lo
g
(
2
)
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